Answer:
7/8 > 5/6
Step-by-step explanation:
A) 7/8
We can compare this as follows.
Lets say both are equal.
Cross multiplying these we get 40=42
We get 40<42. In fraction we get
In case if you want to convert this to decimal, we get;
5/6 = 0.833 and 7/8 = 0.875
We get 5/6<7/8
B) 4/5
Similarly we get 4/5 = 0.8 and 5/6 = 0.833
Here 4/5<5/6
C) 3/4
we get 3/4 = 0.75 and 5/6 = 0.833
3/4<5/6
D) 2/3
we get 2/3 = 0.66 and 5/6 = 0.833
2/3<5/6
Step-by-step explanation:
Answer:

Step-by-step explanation:
Given


Required
The probability model
To do this, we simply calculate the probability of each container.
So, we have:





So, the probability model is:

Answer:

Hopefully, this is your desired setup. (I noticed the formula you have to fill in there.)
Have a good day.
Step-by-step explanation:
Hi.
You could use the percent change formula.
Since we know it is a percent increase then we will do new-old instead of old-new:

x is the new amount of shampoo.
16.5 is the original amount (old) of shampoo.
The percent increase is 30%=0.30 .
So we have the following equation:

We could have found the equation like this:

Subtract 16.5 on both sides:

Divide both sides by 16.5:

By us of symmetric property of equality:

Answer:
y = 8/3
Step-by-step explanation:
x = -2
y = 2/(3*-2) + 3
y = 2/-6 + 3
y = -1/3 + 3
y = -1/3 + 9/3
y = 8/3