Answer:
the answer is p<-9
Step-by-step explanation:
because you divide both sides by 9
Answer:
57.6 km per hr
Step-by-step explanation:
Let us assume the horizontal distance between the ship is constant = x
= 70 Km
The ship A sails south at 40km/h is denoted as 40t
The Ship B sails north at 20 km/h is denoted as 20t
Now the vertical distance separating the two ships is
= 20t + 40t
= 60t
And, the Distance between the ship is changing
![D^2 = y^2 + x^2](https://tex.z-dn.net/?f=D%5E2%20%3D%20y%5E2%20%2B%20x%5E2)
As x is constant
![\frac{\partial x}{\partial t}$ = 0](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpartial%20x%7D%7B%5Cpartial%20t%7D%24%20%3D%200)
Now differentiating
![2D \frac{\partial D}{\partial t}$ = 2y $\frac{\partial y}{\partial t}$](https://tex.z-dn.net/?f=2D%20%5Cfrac%7B%5Cpartial%20D%7D%7B%5Cpartial%20t%7D%24%20%3D%202y%20%24%5Cfrac%7B%5Cpartial%20y%7D%7B%5Cpartial%20t%7D%24)
The distance between two ships is at 4
So,
vertical distance is
![= 60\times 4](https://tex.z-dn.net/?f=%3D%2060%5Ctimes%204)
= 240
And, the horizontal distance is 70
![D = \sqrt{240^2 + 70^2} = 250](https://tex.z-dn.net/?f=D%20%3D%20%5Csqrt%7B240%5E2%20%2B%2070%5E2%7D%20%3D%20250)
![2 \times 250 \frac{\partial D}{\partial T}$ = 2 \times 240 \times 60](https://tex.z-dn.net/?f=2%20%5Ctimes%20250%20%5Cfrac%7B%5Cpartial%20D%7D%7B%5Cpartial%20T%7D%24%20%3D%202%20%5Ctimes%20240%20%5Ctimes%2060)
So, the distance between the ships is 57.6 km per hr
Answer:
a
Step-by-step explanation:
8 (x/4 -6) >= 4
(x/4 - 6) >= 4/8
(x/4) >= 0.5 +6
x >= 6.5 x 4
x>= 26
I don't understand what you mean by 'mentally' but anyways, here is how to solve it.
(z−12)(z+12)
=(z+−12)(z+12)
=(z)(z)+(z)(12)+(−12)(z)+(−12)(12)
=z^2+12z−12z−144
=z^2−144