In which quadrant would point (-11,3)

AnnyKZ [126]

The answer: m∡BCD = 130° .
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Explanation:
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m∡BCD = 9x - 5 = our answer.
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Note: (9x - 5) + (m∡C IN Δ ACB)= 180 ;
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Reason: all angles on straight line add up to 180.
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Note: In Δ ACB; m∡A + m∡B + m∡c = 180.
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Reason: All three angles in any triangle add up to 180.
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Given Δ ACB, we are given:
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m∡C= ?
m∡B = (4x + 5)
m∡A = 65
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So, given Δ ACB; m∡A + m∡B + m∡c = 180;
→Plug in our known values and rewrite:
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Given Δ ACB; 65 + 4x + 5 + (m∡c) = 180;
→Simplify, and rewrite:
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Given Δ ACB; 4x + 70 + (m∡c) = 180;
→Subtract "70" from each side of the equation; and rewrite:
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Given Δ ACB; 4x + (m∡C) = 110;
→Subtract "4x" from EACH SIDE of the equation; to isolate: "(m∡c)" on one side of the equation; and "solve in terms of "(m∡C)" ;
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Given Δ ACB' m∡C = 110 - 4x ;
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So, we know that: (110 - 4x) + (9x - 5) = 180; (since all angles on a straight line add up to 180.
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We can solve for "x".
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(110 - 4x) + (9x - 5) = 180;
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Rewrite as:
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(110 - 4x) + 1(9x - 5) = 180 ; (Note: there is an implied coefficient of "1"; since anything multiplied by "1" equals that same value).
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Note the "distributive property of multiplication":
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a*(b+c) = ab + ac ; AND:
a*(b - c) = ab - ac .
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So, +1(9x - 5) = (+1*9x) - (+1*5) = 9x - 5 ;
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So we can rewrite:
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(110 - 4x) + (9x - 5) = 180 ; as:
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110 - 4x + 9x - 5 = 180 ; We can simplify this by combining "like terms" on the "left-hand side" of the equation:
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110 - 5 = 105 ;
-4x + 9x = 5x;
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So, rewrite as: 5x + 105 = 180; Subtract "105" from EACH side; to get:
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5x = 75 ; Now, divide each side of the equation by "5";
to get: x = 15.
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Now, we want to know: m∡BCD; which equals:
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9x - 5 ; let us substitute "15" for "x"; and solve:
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9x - 5 = 9*(15) - 5 = 135 - 5 = 130.
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The answer: m∡BCD = 130°
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6 0

3 years ago

The height of a triangular window is 3 feet less than its base. The area the window is 20 ft.? find the dimensions of the window

Ivenika [448]

Let us assume base of the window = b feet.

Height is 3 feet less than base, that is = (b-3).

Given area of the triangle = 20 feet square.

We know formula for area of a triangle:

Area = $\frac{1}{2}$ × Base × Height

Plugging values in formula, we get

20 = $\frac{1}{2} b \times (b-3)$

$\mathrm{Multiply\:both\:sides\:by\:}2$

$40=b\left(b-3\right)$

$40=b^2-3b$

$b^2-3b-40=0$

Factoring quadratic, we get

$\left(b+5\right)\left(b-8\right)$ =0

b+5=0

b=-5

b-8=0

b=8.

For base we can take only positive value.

<h3>Therefore, base of the triangle = 8 feet and height = 8 -3 = 5 feet.</h3>

6 0

3 years ago

SOMEONE HELP ME PLSSS!

Tomtit [17]

Answer:

y is 1 and x is 4

Step-by-step explanation:

becasue the y intercepts at 1 and the x intercepts at 4

8 0

3 years ago

Read 2 more answers

The angels of a triangle have a sum of 180°. The angles of a rectangle have a sum of 360°. The angels of a pentagon have a sum o

Airida [17]

Step-by-step explanation:

It is given that the angels of a triangle have a sum of 180°. The angles of a rectangle have a sum of 360°. The angels of a pentagon have a sum of 540.

<u>Let me define the each terms.</u>

1. We know that each angle in a triangle is 60°, So there is a three angle in a regular triangle.

60° + 60° + 60°
180°

2. We know that each angle in a rectangle, is 90°, So there is a four angle in a regular rectangle.

90° + 90°+90°+90°
360°

Similarly,

There is 8 angle in a regular octagon and each angle measurement is 135°.

So, sum of the angles of an octagon = 135° × 8

Sum of the angles of an octagon = 1080°

Therefore, the required sum of the angles of an octagon is 1080°

6 0

3 years ago

What are all the solutions? <br> 4x^2+9y^2=72<br> x^2+y^2=5

Ilya [14]

There is no solution.
If you graph both equations they never touch.

4 0

3 years ago

Read 2 more answers

In which quadrant would point (-11,3)​

In which quadrant would point (-11,3)