Question

Find the value of the expression: a. 3x^0 for x=2.6, b. 10a^2b^0 for a=–3, b=–8

Answer 1

Step-by-step explanation:

For x = 2,6

$= 3{x}^{0}$

$= 3 \times {2,6}^{0}$

$= 3 \times1$

$= 3$

$\:$

For a = -3 and b = -8

$= 10 \times {a}^{2} \times {b}^{0}$

$= 10 \times {( - 3)}^{2} \times {( - 8)}^{0}$

$= 10 \times 9 \times 1$

$= 90$