3 years ago

If cot xº = 3/4 what is the value of b?

Mathematics

1 answer:

balandron [24]3 years ago

3 0

Answer:

$\cot(x) = \frac{3}{4} = \frac{10.5}{2b}$

$4 \times 10.5 = 2 b \times 3$

$42 = 6b$

$b = 7$

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The other endpoint is (1, -17).

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$m=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

Using our midpoint and endpoint, we have:
$(6, -11) = (\frac{11+x_2}{2}, \frac{-5+y_2}{2})
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For the first equation (to find the x-coordinate) we will multiply both sides by 2:
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