Question

Which situation has the greatest rate of change? Filling a swimming pool with 100 gallons of water in 15 minutes or pumping 12 gallons of gas into your tank in 3 minutes?

Answer 1

Answer:

Pumping gas into take with greater rate of change.

Step-by-step explanation:

Rate of change is equal to change in number of gallons per minutes.

Here we have two case

Case 1: Filling swimming pool with 100 gallons of water in 15 minutes.

So, we find how many gallons fill in 1 minutes.

$\text{Rate }=\frac{\text{Number of gallons}}{\text{Total minutes}}$

$\text{Rate }=\frac{100}{15}\approx 6.67\text{ gallons/min}$

Case 2: Pumping 12 gallons of gas into tank in 3 minutes.

So, we find how many gallons fill in 1 minutes.

$\text{Rate }=\frac{\text{Number of gallons}}{\text{Total minutes}}$

$\text{Rate }=\frac{12}{3}\Rightarrow 4\text{ gallons/min}$

Rate of case 2 is greater than case 1.

Thus, Pumping gas into tank with greater rate of change.