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bulgar [2K]
3 years ago
15

I am a quantity that can change or vary, taking on different values. Who am I?

Mathematics
2 answers:
Zigmanuir [339]3 years ago
8 0
The answer is You are a variable
vodka [1.7K]3 years ago
6 0
Obiouly  the answer is X because X can change values and could vary anyway is X
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Use the given inverse to solve the system of equations. left brace Start 3 By 3 Matrix 1st Row 1st Column x minus y plus z 2nd C
natka813 [3]

The interpretation of the given question is as follows:

Use the given inverse to solve the system of equations

x- y - z = -6  \\ \\ 2y + z = -6 \\ \\  3x -8 y = - \dfrac{1}{2}

The inverse of  \left[\begin{array}{ccc}1&-1&1\\0&2&1\\3&-8&0\end{array}\right]   is \left[\begin{array}{ccc}-8&8&3\\-3&3&1\\6&-5&-2\end{array}\right]

x =

y =

z =

Answer:

x = - 1.5

y = - 0.5

z =  - 5

Step-by-step explanation:

Using the correlation  of inverse of matrix AX = B to solve the question above;

AX = B

⇒ A⁻¹(AX)  = A⁻¹ B

X =  A⁻¹ B

So ;

X         =        A⁻¹                             B

\left[\begin{array}{c}x\\y\\z\end{array}\right] =     \left[\begin{array}{ccc}-8&8&3\\-3&3&1\\6&-5&-2\end{array}\right] =   \left[\begin{array}{ccc}-6\\ -6\\- \dfrac{1}{2}\end{array}\right]

   

 \left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}(-8*-6)+(8*-6)+(3*-\dfrac{1}{2})\\(-3*-6)+(3*-6)+(1*-\dfrac{1}{2})\\(6*-6)+(5*-6)+(-2* - \dfrac{1}{2})\end{array}\right]

\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}(48)+(-48)+(\dfrac{-3}{2})\\(18)+(-18)+(\dfrac{-1}{2})\\(-36)+(30)+(1)\end{array}\right]

\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}(\dfrac{-3}{2})\\(\dfrac{-1}{2})\\(-5)\end{array}\right]

\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}-1.5\\-0.5\\ -5\end{array}\right]

5 0
3 years ago
Solve for all values of p: ​
Alchen [17]

Answer:

p = - 5, p = - 1

Step-by-step explanation:

Given

\frac{3p}{p-5} - \frac{2}{p+3} = \frac{p}{p+3}

Multiply through by the LCM of (p - 5)(p + 3)

3p(p + 3) - 2(p - 5) = p(p - 5) ← distribute parenthesis

3p² + 9p - 2p + 10 = p² - 5p

3p² + 7p + 10 = p² - 5p ( subtract p² - 5p from both sides )

2p² + 12p + 10 = 0 ← divide through by 2

p² + 6p + 5 = 0 ← in standard form

(p + 1)(p + 5) = 0 ← in factored form

Equate each factor to zero and solve for p

p + 1 = 0 ⇒ p = - 1

p + 5 = 0 ⇒ p = - 5

3 0
3 years ago
Jeffrey set up chairs for a meeting.
Kazeer [188]

Answer:

9x + 3 = 7x + 19

Step-by-step explanation:

Given that,

Jeffrey set up chairs for a meeting.

He arranged the chairs in 9 equal  rows but had 3 chairs left over.

Let x be the number of chairs. So,

9x+3 .....(1)

Then he arranged the chairs in 7 equal rows  but had 19 chairs left over. So,

7x+19 ......(2)

From equation (1) and (2),

9x+3 = 7x+19

9x-7x = 19-3

2x = 16

x = 8

Hence, the correct option is (b).

3 0
2 years ago
Select the point that is a solution to the system of inequalities​
ExtremeBDS [4]
<h3>Answer: B.  (-1, 0)</h3>

This point is below both the red diagonal line and the blue parabola. We know that the set of solution points is below both due to the "less than" parts of each inequality sign.  

In contrast, a point like (2,2) is above the parabola which is why it is not a solution. It does not make the inequality y \le x^2-3x true. So this is why we can rule choice A out.

Choice C is not a solution because (4,1) does not make y \le -x+3 true. This point is not below the red diagonal line. We can cross choice C off the list.

Choice D is similar to choice A, which is why we can rule it out as well.

5 0
3 years ago
Shelly can cut a lawn with a riding mower in 22 hours less time than it takes william to cut the lawn with a push mower. if they
umka2103 [35]
Let n be the amount of time it takes william to cut the lawn. Then Shelly takes
n-2 hours. So:
1/n+1/n-2=1/3
3(n-2)+3n=n²-2n
6n-6=n²-2n
n²-8n+6=0
Using the quadratic formula, we get a positive value of 7.1623 hrs as the amount of time william takes working alone, and 5.1623 as the amount  of time Shelly takes working alone
☺☺☺☺
7 0
3 years ago
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