REVISED
Answer:
x = 15.33
Step-by-step explanation:
3y is equal to 2x + 13. The reason why is because they are corresponding angles, (right next to each other). From there, you would have to substitute y into 3y. The equation should look like: 3(23) = 2x + 13. All that is left is to solve for x.
This is a 45-45-90 triangle. The side facing the 90 degree angle would be the a square root 2. The sides facing the 45 degree angles would be a. 2 square root 2 is facing a 45 degree angle, so that means the side facing the 90 degree angle would be 2 square root 2 x square root 2 which is 4. Basically:
a = 4
b = 2 square root 2
Answer:
The 90% confidence interval for the mean weight of all adult male grizzly bears in the United States is between 573 pounds and 649 pounds.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 23 - 1 = 2
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 22 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.0739
The margin of error is:
![M = T\frac{s}{\sqrt{n}} = 2.0739\frac{89}{\sqrt{23}} = 38](https://tex.z-dn.net/?f=M%20%3D%20T%5Cfrac%7Bs%7D%7B%5Csqrt%7Bn%7D%7D%20%3D%202.0739%5Cfrac%7B89%7D%7B%5Csqrt%7B23%7D%7D%20%3D%2038)
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 611 - 38 = 573 pounds
The upper end of the interval is the sample mean added to M. So it is 611 + 38 = 649 pounds
The 90% confidence interval for the mean weight of all adult male grizzly bears in the United States is between 573 pounds and 649 pounds.
I can’t see a picture so don’t know what they look like