Answer:
the first one is
+2 +4 + 8 + 16 +32
he multiply by 2 every time he add numbers so its 65
the second one he make this
-8 -4 -2 -1
every time he Take from numbers he devide by 2
so its 5
the third one
+6 +18 + 54 + 162
every time he add he multiply by 3
ao its 162 +80 =242
the fourth one is
+33 +66 + 132 +264
he multiply by 2 every time he add
so its 267+264=531
the fiveth one is
he put the roots
2²,3²,4²,5²,6²
so the answer is 36
Step-by-step explanation:
A 65
B 5
C 242
D 531
E 36
hopefully its helpful man
Answer:
45
Step-by-step explanation:
Two tangents drawn to a circle from an outside point form arcs and an angle, and this formula shows the relation between the angle and the two arcs.
m<EYL = (1/2)(m(arc)EVL - m(arc)EHL) Eq. 1
The sum of the angle measures of the two arcs is the angle measure of the entire circle, 360 deg.
m(arc)EVL + m(arc)EHL = 360
m(arc)EVL = 360 - m(arc)EHL Eq. 2
We are given this:
m<EYL = (1/3)m(arc)EHL Eq. 3
Substitute equations 2 and 3 into equation 1.
(1/3)m(arc)EHL = (1/2)[(360 - m(arc)EHL) - m(arc)EHL]
Now we have a single unknown, m(arc)EHL, so we solve for it.
2m(arc)EHL = 3[360 - m(arc)EHL - m(arc)EHL]
2m(arc)EHL = 1080 - 6m(arc)EHL
8m(arc)EHL = 1080
m(arc)EHL = 135
Substitute the arc measure just found in Equation 3.
m<EYL = (1/3)m(arc)EHL
m<EYL = (1/3)(135)
m<EYL = 45
It does not contain an equal sign. It cannot be solved for unless the value of the variable is given.
Answer:
Step-by-step explanation:
To solve this problem is multiply 2 by 2 and then 2 which gives you 8.
Then you will add 2+2+2 and get six. For when multiply exponents you are adding.
Step-by-step explanation:
you must have made a typo here.
none of the answer options are correct for the given problem.
let me just show you what you told me, and how I can solve at least this :
2a/4 = b/4
this simply means (multiply both sides by 4) :
2a = b
so, 5b is then (multiplying both sides by 5) :
5×2a = 5b
10a = 5b
but again, "10a" is not among the offered answers.
so, I don't know if you made a mistake with the basic problem or with the answer options.
