m = (y2-y1)/(x2-x1)
m = (6-4)/(4-0)
m = 2/4
y = mx + c
6 = (2/4)(4) + c
c = 4
Thus, the equation is y = (2/4)x +4
Answer:
i dont really know
Step-by-step explanation:
i am doing this for the point things
p(x)= x-2
g(x)= 2x^3 + 3x^2 - 11x - 6
first we have to find the zero of the polynomial of x-2
p(x)= x-2 = 0
x=2
therefore,
p(x)= 2x^3 + 3x^2 - 11x - 6
p(2)= 2*2^3 + 3*2^2 - 11*2 - 6
= 2*8 + 3*4 - 11*2 - 6
= 16 + 12 - 22 - 6
= 28-28
= 0
Hope it helped u, ^_^.
The answer is D! if you sub them in :)
Answer:
No.
Step-by-step explanation:
Try the vertical line test. If the lines intersect or connect at some point, then it's not a function. Do you want to practice with some Ixls to help, or use some images for reference?
