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Akimi4 [234]
3 years ago
14

Find the area of the shaded region. Round to the nearest hundreth where necessary.

Mathematics
1 answer:
Jet001 [13]3 years ago
3 0

Answer:

192.42 m²

Step-by-step explanation:

big circle

10.5 ² x   pi =346.3605

inner circle

 7 ² x pi = 153.9380

346.3605 -  153.9380 = 192.4225   (192.42)

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See the attachment below for the question.
hram777 [196]

Answer:

5.631

Step-by-step explanation:

3^x-4 = 6

<u>Add log to both sides</u>

<em>A^x = Y</em>

<em>x logA = logY</em>

<em>3^x-4 = 6</em>

<em>(x-4) log 3 = log 6</em>

<em>x - 4 = log 6/log 3</em>

<em>x - 4= 1.631</em>

x = 5.631

Therefore, the value of x is 5.631.

!!

8 0
3 years ago
What is your guys opinion on Highschool DxD<br> Also here all of my points
Ahat [919]

Answer:

I didnt reeally like the anime but I watched it still.I prefer angels of death still.

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Industry standards suggest that 8 percent of new vehicles require warranty service within the first year. Jones Nissan in Sumter
jenyasd209 [6]

Answer:

Step-by-step explanation:

Let X be the no of vehicles that require warranty service within I year out of vehicles sold (9) yesterday.

Each vehicle is independent of the other to get warranty service

Hence X is binomial with p=8% = 0.08

So P(X=x) = 9Cx (0.08)^x (1-0.08)^{9-x} ,x=0,1,2...9

a) P(X=0) = 0.472161\\b) P(x=1) = 0.3695

c) P(X=2) = 0.1285

d) Mean = Mean of binomial = np =

9(0.08) = 0.72

Var (x) = npq = 0.6624

Std dev = square root of variance = 0.8139

5 0
3 years ago
Read 2 more answers
How should I go about solving this question?
Verdich [7]

Answer:

A radius of a circle or sphere is any of the line segments from its center to its perimeter, and in more modern usage, it is also their length

Step-by-step explanation:

3 0
2 years ago
In the equation (x^2+y)^5, what is the coefficient of the term x^4y^3? what is the coefficient of the same term in the expansion
lys-0071 [83]

\displaystyle&#10;(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k

<em>-------------------------------------------------------------</em>


\displaystyle&#10;(x^2+y)^n=\sum_{k=0}^n\binom{n}{k}x^{2n-2k}y^k\\&#10;n=5\\&#10;k=3\\\\\binom{5}{3}=\dfrac{5!}{3!2!}=\dfrac{4\cdor5}{2}=10

<u>It's 10.</u>

----------------------------------------------------

\displaystyle&#10;(3x^2+y)^n=\sum_{k=0}^n\binom{n}{k}(3x)^{2n-2k}y^k=\sum_{k=0}^n\binom{n}{k}\cdot 3^{2n-2k}\cdot x^{2n-2k}y^k\\\\&#10;n=5\\&#10;k=4\\\\&#10;\binom{5}{3}\cdot3^{2\cdot5-2\cdot4}=10\cdot3^{2}=10\cdot9=90

<u>It's 90</u>

6 0
3 years ago
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