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Fed [463]
3 years ago
9

Which of these is an example of a mixture?

Biology
2 answers:
alexgriva [62]3 years ago
8 0

Answer:

e

Explanation:

Salt water does not have a uniform composition and we can divide salt and water by simple physical process of evaporation (by boiling the salt water). Thus, salt water is a mixture, with salt as the solute and water as the solvent. In fact, salt water is a homogeneous mixture and can be termed as a solution

never [62]3 years ago
6 0
B: hydrogen peroxide
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C using a scanning electron microscope
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URGENT URGENT URGENT HELP ME PLS <br> List and describe ways to reduce human footprint on Earth.
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Taking shorter showers

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In a particular case of secondary succession, three species of wild grass all invaded a field. By the second season, a single sp
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Answer:

In a particular case of secondary succession, three species of wild grass all invaded a field. By the second season, a single species dominated the field and the other two species had a lower relative abundance. A possible factor contributing to the abundances of these species in this example of secondary succession is <u>inhibition</u>.

Explanation:

Trees are great examples of allelopathy in plants. Some use their allelochemicals to inhibit germination or impede development of nearby plant life. Most allelopathic trees release these chemicals through their leaves, which are toxic once absorbed by other plants. Black walnut is a prime example of this.

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3 years ago
In guinea pigs hair straightness or curliness is thought to be governed by a single pair of alleles showing incomplete dominance
Nimfa-mama [501]

Answer:

Frequency of allele S is p = 0.4939

Frequency of allele C is q = 0.666

The population is not in Hardy-Weinberg equilibrium

Explanation:

Given -

Number of individuals with straight hair = 244

Number of individuals with curly hair = 444

Number of individuals with Wavy hair = 312

Let "p" represents the frequency for allele for straight hair and "q" represents the frequency for allele for curly hair

p^2 represents the frequency of genotype "SS"

p^{2} = \frac{244}{1000} \\= 0.244

q^2 represents the frequency of genotype "CC"

p^{2} = \frac{444}{1000} \\= 0.444

2pq represents the frequency of genotype "SC"

2pq = \frac{312}{1000} \\= 0.312

Frequency of allele S is p

= \sqrt{0.244} \\= 0.4939

Frequency of allele C is q

tex]= \sqrt{0.444} \\= 0.666[/tex]

For being in Hardy Weinberg's equation-

p+q=1\\

Substituting the values in above equation, we get -

0.4939+0.666\neq 1

hence, the population is not in Hardy-Weinberg equilibrium

4 0
3 years ago
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