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tankabanditka [31]
3 years ago
7

1.) The individual letters of the word CLASSICALLY are written on pieces of paper and placed in a hat. One letter is selected at

random. Find the odds against selecting the letter C.
2.) A bag of peanut M&M's contains 17 green candies, 16 red candies, 13 blue candies, 12 orange candies, 11 brown candies, and 14 yellow candies. One M&M candy is selected at random. Find the odds against selecting a blue candy.
Give your answer as a ratio in the form of a:b. Do not simplify your ratio.

3.)A recent study conducted by Who's The Baby Now? shows that the odds in favor of a male between the ages of 18 - 26 being afraid of spiders is 3:262. Based on this report, what would be the probability that a randomly selected male in this age group would be afraid of spiders?
Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
5 0

Answer:

1.) 9/11

2.)13/70

3.)the number would increase by 2%

Step-by-step explanation:

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Given csc(A) = 60/16 and that angle A is in Quadrant I, find the exact value of sec A in simplest radical form using a rational
fiasKO [112]

Answer:

\frac{15 \sqrt{209} }{209}

Step-by-step explanation:

Objective: Understand and work with trig identies.

Recall multiple trig identies and manipulate them to get from cosecant to secant.

Given

\csc(a)  =  \frac{60}{16}

Apply reciprocal identity csc a = 1/sin a.

\sin(a)  =  \frac{16}{60}

Apply pythagorean identity to find cos a.

( \frac{16}{60})  {}^{2}  +   \cos(x) {}^{2}  = 1

\frac{256}{3600}  +  \cos(x)  {}^{2}  = 1

\cos(x)  {}^{2}  =  \frac{3600}{3600}   -  \frac{256}{3600}

We can simplify both expression

\cos(x)  {}^{2}  =  \frac{225}{225}  -  \frac{16}{225}

\cos(x)  =  \frac{ \sqrt{209} }{15}

Cosine is positve on quadrant 1 so that cos(a)

Apply reciprocal identity sec a= 1/ cos a.

The answer is

\sec(a)  =  \frac{15}{ \sqrt{209} }

Rationalize the denominator.

\frac{15}{ \sqrt{209} }  \times  \frac{ \sqrt{209} }{ \sqrt{209} }  =  \frac{15 \sqrt{209} }{209}

3 0
3 years ago
Lana took one and a half times as long as jayden to finish a project. If Lana took 15 days, how long did Jayden take ?
aev [14]
10 days. 15 divided by 1.5 is 10
6 0
3 years ago
Casey bought a 100 pound bag of dog food for his dogs. Casey gave them the same amount of dog food each week. The dog food laste
sertanlavr [38]

12.5 pounds

100 pounds / 8 = 12.5 pounds

4 0
3 years ago
A library subscribes to two different weekly news magazines, each of which is supposed to arrive in Wednesday's mail. In actuali
Zinaida [17]

Answer:

See pmf of Y below

Step-by-step explanation:

Let's abbreviate the days by using the first letter, W, T, F and S.

The following array shows the possible probabilities for Y.

Since the probabilities are independent Y(a,b) = P(a)*P(b) for any day a,b.  

The array shows the pmf of Y, that is, the probability that the number of days <em>beyond TUESDAY</em> (as we are considering W) that it takes for both magazines to arrive after Wednesday equals to or is greater than 0.

\bf \left[\begin{array}{ccccc}Day&W&T&F&S\\W&0.28^2&0.28*0.38&0.28*0.21&0.28*0.13\\T&0.38*0.28&0.38^2&0.38*0.21&0.38*0.13\\F&0.21*0.28&0.21*0.38&0.21^2&0.21*0.13\\S&0.13*0.28&0.13*0.38&0.13*0.21&0.13^2\end{array}\right]

computing the probabilities, we get the array

\bf \left[\begin{array}{ccccc}Day&W&T&F&S\\W&0.0784&0.1064&0.0588&0.0364\\T&0.1064&0.1444&0.0798&0.0494\\F&0.0588&0.0798&0.0441&0.0237\\S&0.0364&0.0494&0.0273&0.0169\end{array}\right]

The right way to read Y is Y(row,column). For example, the probability that magazine 1 arrives on Thursday and magazine 2 arrives on Friday is Y(T,F) = 0.0798.

3 0
3 years ago
Pls help me! Due in like, 5 minutes and I am stuck on this question! 20 points and brainliest!
MrRa [10]

Answer:

9 times

Step-by-step explanation:

7 0
3 years ago
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