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3 years ago

What is the value of sin 0 given that (-3,7) is a point on the terminal side 0

Mathematics

1 answer:

aliina [53]3 years ago

8 0

Answer:

$\frac{7\sqrt{58}}{58}$

Step-by-step explanation:

$\\\text{Given that a point on the terminal side of }\theta \text{ is }(-3,7)\\\\\text{so the terminal side is in Quadrant II}\\\\\text{In the right triangle OMN, using Pythagorean theorem, we get}\\\\\text{ON}=\sqrt{(MN)^2+(OM)^2}\\\\\Rightarrow ON=\sqrt{(7)^2+(-3)^2}\\\\\Rightarrow ON=\sqrt{49+9}\\\\\Rightarrow ON=\sqrt{58}\\$

$\\\text{we know that in Quadrant II, sine and cosecant are positive.}\\\text{so using the trigonometric ratios, we get}\\\\\sin \theta=\frac{\text{Opposite }}{\text{Hypotenus}}\\\\\Rightarrow \sin \theta=\frac{7}{\sqrt{58}}\\\\\Rightarrow \sin \theta=\frac{7\sqrt{58}}{58}\\$

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Abbot is paid weekly for every hour he works. He worked 6 hours each day for 5 days last week. He earned $408, before taxes. Wri

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Answer:

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A box of oat cereal costs $3.90 for 15 ounces. A box of rice of cereal costs $3.30 for 11 ounces. Which box of cereal costs less

Firlakuza [10]

Answer:

The cost of per ounce of oat cereal is $0.04 less than per ounce cost of rice.

Step-by-step explanation:

Given:

Cost of 15 ounces of oat cereal box = $3.90

Cost of 11 ounces of rice box = $3.30

To compare the unit prices of the the boxes.

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Using unitary method to find the unit prices:

If 15 ounce of oat box cost =$3.90

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∴ Per ounce cost of oat cereal = $0.26

If 11 ounce of rice box cost =$3.30

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∴ Per ounce cost of rice = $0.3

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3 years ago

A function has a y-intercept of -6 and x-intercepts at (2,0) and (6,0). Which graph represents this function?

LuckyWell [14K]

Answer: I'm guessing it would be a parabola, with the line going through -6 on the y-axis and passing through 2 and 6 on the x-axis, but we cannot see any answers, so therefore we can't answer it accurately.

Step-by-step explanation:

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kompoz [17]

I need some points so I put this

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3 years ago

Read 2 more answers

Help me idk how to do this

ElenaW [278]

To do this, you have to plug each x value into the rule.

1.y = 15 - 3×2
y = 15 - 6
y = 9

So the first y value would be 9.

2.y = 15 - 3×3
y = 15 - 9
y = 6

3. y = 15 - 3×4
y = 15-12
y = 3

4. y = 15 - 3×5
y = 15-15
y = 0

Hope this helps!

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3 years ago