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3 years ago

WILL MARK THE BRAINIEST!!! LOTS OF POINTS!! HELP NOW

Mathematics

1 answer:

ElenaW [278]3 years ago

3 0

cos (arctan (1))=

arctan (1) = 45 take it to the third quadrant = add 180 = 225

cos (225) = -1 / sqrt(2)

never leave a sqrt in the denominator

= -1 /sqrt(2) * sqrt(2)/sqrt(2)

= -sqrt(2)/2

sin (arccos (1/2)

arccos (1/2) = 60 take it to the 4th quadrant -60 degrees

sin (-60)

- sin 60

- sqrt(3)/2

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Let f(x)=x-1,h(x)=-x+4. Find (f o h)(4). (f o h)(4)=

bagirrra123 [75]

Answer:

-1

Step-by-step explanation:

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f(0) = 0-1 = -1

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3 years ago

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How do I obtain the real number solutions to the polynomial function f(x)=x^3 - 4x^2 + x +6?

Svetlanka [38]

$\bf f(x)=x^3-4x^2+x+6\\\\
-----------------------------\\\\

\begin{array}{l|lrrrrllllll}
3&&1&-4&1&6\\
&&&3&-3&-6\\
--&&--&--&--&--\\
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\end{array}\impliedby x=3\implies (x-3)=0
\\\\\\
\textit{that give us the factors of }
\\\\\\
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\\\\\\
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4 0

4 years ago

Alexus [3.1K]

Answer:

1. 10mn - 35 2. 8rs -2r + 16

Step-by-step explanation:

10mn - 35

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3 0

3 years ago

A new sample of 225 employed adults is chosen. Find the probability that less than 7.1% of the individuals in this sample hold m

arsen [322]

Answer:

The probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.

Step-by-step explanation:

Let X = number of individuals in the United States who held multiple jobs.

The probability that an individual holds multiple jobs is, p = 0.13.

The sample of employed individuals selected is of size, n = 225.

An individual holding multiple jobs is independent of the others.

The random variable X follows a Binomial distribution with parameters n = 225 and p = 0.13.

But since the sample size is too large Normal approximation to Binomial can be used to define the distribution of proportion p.

Conditions of Normal approximation to Binomial are:

np ≥ 10
n (1 - p) ≥ 10

Check the conditions as follows:

$np=225\times 0.13=29.25>10\\n(1-p)=225\times (1-0.13)=195.75>10$

The distribution of the proportion of individuals who hold multiple jobs is,

$p\sim N(p, \frac{p(1-p)}{n})$

Compute the probability that less than 7.1% of the individuals in this sample hold multiple jobs as follows:

$P(p$

*Use a z-table.

Thus, the probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.

7 0

3 years ago