If you would like to solve the equation<span> (a - c) / (x - a) = m for x, you can do this using the following steps:
</span><span>(a - c) / (x - a) = m
</span>a - c = m * (x - a)
a - c = mx - ma
mx = a - c + ma
x = (a - c + ma) / m
x = a/m - c/m + a
The correct result would be <span>x = a/m - c/m + a.</span>
<span>(5,-1)
The key to this problem is ignoring all the information that you don't need. You really don't care about the coordinates for T, U, or V. Just W is all that matters. So make a graph, label the X and Y axis, and put a point at (1,5). Now simply turn the entire paper clockwise 90 degrees. If you do this, you'll see that what was the X axis is now the Y axis. And what was the Y axis is now the X axis. Label the axis again, and read the location of the point you marked. If you do so, you'll see that you have to go 5 spaces along the X axis, hence the 5. And you'll go 1 space down on the Y axis, hence the -1.
So the coordinates of W(1,5) rotated 90 degrees clockwise around (0,0) changes to (5,-1).</span>
Answer:
27 =s
Step-by-step explanation:
9=s/3
We want to isolate s, so we will multiply by 3 on each side
9*3 = s/3 *3
27 =s
Answer is 3 seconds
When the bullet reaches the ground, ground being x in graph (and here its s which is = 0)
s = -16t^2 + 48t
s = 0, solve for t
0 = -16t^2 + 48t
0 = t ( -16t + 48)
0 = 16t ( - t + 3)
now you have two equation
0 = 16t and 0 = -t +3 ( you can look at the graph line touches x twice)
0 = 16 t
0 = t ( you know its false, because time = 0)
You are left with
0 = -t + 3
t = 3
It takes 3 seconds for the bullet to return to the ground.
// Hope this helps.
Answer:
I think its c
Step-by-step explanation:
