Ask question

Ask question

All categories

3 years ago

14

Sara found 58 seashells on the beach,she gave Dan some of her seashells.She has 13 seashells left.How many seashells did she giv

e to Dan?

2 answers:

Salsk061 [2.6K]3 years ago

5 0

58-13 that she has left = 45
She gave 45 to Dan

olasank [31]3 years ago

5 0

58-13= 45 you just have to subtract:)

You might be interested in

Braden is coaching a youth soccer team, which has eight players. At the end of a tied game, Braden's team must go into a shootou

cupoosta [38]

Randomly select a chip from a bucket containing eight chips, whick are each uniquely labeled with each child's name

8 0

3 years ago

What is the solution to 3 times the square root of 4 minus 2 times the square root of 4? A. 0 B. 1 C. 2 D. 3

olasank [31]

For this case we have the expression:

"the square root of 4" is represented algebraically as:

$\sqrt {4}$

Then, we can express the given statement as:

$3 \sqrt {4} -2 \sqrt {4} =$

They are similar terms, we can subtract:

$3 \sqrt {4} -2 \sqrt {4} = \sqrt {4} = \sqrt {2 ^ 2}$

By definition of power properties we have that:

$\sqrt [n] {a ^ n} = a ^ {\frac {n} {n}} = a$

Then the expression is reduced to:

$\sqrt {2 ^ 2} = 2$

Answer:

$3 \sqrt {4} -2 \sqrt {4} = 2$

8 0

3 years ago

Which expression is equivalent to the expression 22 – 10 – 7.5?

Sergeu [11.5K]

Answer:

24.5-9-6

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What was John’s age 4 years ago, if he is y years old now?

n200080 [17]

To find his age 4 years ago, you need to subtract 4 from his current age.

His current age is Y, so his age 4 years ago is: y - 4

8 0

3 years ago

an object falls 16t2 feet in t seconds. you drop a rock from a bridge that is 75 feet above the water. will the rock hit the wat

Goryan [66]

Answer:

No, the rock will not hit the water in 2 second but it will hit the water in t ≅ 2.17 second

Step-by-step explanation:

Let the distance be s in feet. i.e, $s= 16 t^2$ where t is in second.

You drop a rock from a bridge that is 75 feet above the water.

Use the expression $s =16t^2$ to solve for t:

Given: s =75 feet

then, substitute in the above expression:

$75 = 16 t^2$ or we can write it as:

$t^2=\frac{75}{16}= 4.6875$ or

$t = \sqrt{4.6875}$

⇒ t = 2.16506351 or t ≅2.17 second

Therefore, the rock hit the water in t≅2.17 second

5 0

3 years ago