Can someone answer this question please?

Emily, Frances, and Bill each carried a 10-pound bag of soil into the backyard. After putting the soil in the first flower bed,

Art [367]

Step-by-step explanation:

emily: 10(5/8) = 6 1/4 or 6.25 pounds left

10- 6.25 = 3.75 used

Frances : 10(2/5) = 4 pounds left

10-4 = 6 pounds used

Bills : 10(2/5) = 4 pounds left

10-4 = 6 pounds used

add them together

15.75 or 15 3/4 pounds of soil in the first flower bed

6 0

3 years ago

Sam is loading a freight elevator with boxes that are 55 pounds each. If the freight elevator can safely hold up to 3000 lbs, ho

bixtya [17]

Answer:

54

Step-by-step explanation:

$\frac{3000}{55} \\ = 54.5454...$

Therefore, Sam can put 54 boxes.

8 0

3 years ago

4t+14=6t/5+7 what is the answer

Oliga [24]

4t+ 14= 6t/5+ 7
⇒ 4t+ 14= 6/5t+ 7
⇒ 4t -6/5t= 7 -14
⇒ (4 -6/5)t= -7 (distributive property)
⇒ 14/5t= -7
⇒ t= -7/ (14/5)
⇒ t= -5/2
⇒ t= -2.5

Final answer: t= -2.5~

7 0

3 years ago

7 Point Question Tyler was trying to prove that all rhombuses are similar. He thought, “If I draw 2 rhombuses, I can find dilati

Viefleur [7K]

A rhombus can have the same shape and dimension as a square or a

parallelogram, therefore, all rhombuses are not similar.

A step in the proof that have flaws is <u>step 3</u>.

Reasons:

By reading through the given steps, we have, the first step that is incorrect

is step 3.

Step 3: The requirement for the similarity of two figures based on the

proportionality of the corresponding sides of the figures is related with

triangles as given by the triangle proportionality theorem.

This is so because, the lengths of the sides of a triangle depends on the

opposite interior angle, while the side of a rhombus can have a

combination of large length and and acute angle.

Two rhombuses that have proportional sides may be dissimilar,

because they can have different interior angles.

Therefore;

<u>The step in Tyler's proof that have a flaw is Step 3</u>

Learn more about similarity between geometric figures here:

brainly.com/question/10270676

7 0

2 years ago

SOMEONE PLEASE HELP ANSWER MY QUESTIONS!!!!!!!!!!!!

Semmy [17]

1)
$y=mx+b$
where m is the slope

We know the slope is 5 and the line passes through the point (4,3).

$m=5 \\
(4,3) \\
x=4 \\ y=3 \\ \\ 
3=5 \times 4 + b \\
3=20 + b \\
b=3-20 \\
b=-17$

The equation of the line is:
$y=5m-17$

Now the second point:
$(2,y) \\
x=2 \\
y \\ \\ y=5 \times 2 -17 \\ y=10-17 \\ y=-7$

The answer:
The value of y is -7.

2)
The line passes through the origin, or the point (0,0), and has a slope of -32.
The slope is negative so the line goes down from left to right.
It crosses both x and y axes in the point (0,0).
Therefore, it only passes through II and IV quadrant.

You can also find the equation of the line, find one more point and draw it.
$y=mx+b \\ \\
m=-32 \\
(0,0) \\
x=0 \\ y=0 \\ \\
0=-32 \times 0 + b \\
b=0 \\ \\
y=-32x$

Find the y-coordinate of the point for example (1,y).
$(1,y) \\
x=1 \\ y \\ \\
y=-32 \times 1 \\
y=-32$

The line passes through the points (0,0) and (1,-32). Now you can draw it (see the attachment).

The answer:
The line passes through quadrants II and IV.

4 0

3 years ago