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Ahat [919]
3 years ago
10

Point C has the coordinates (-1,4) and point D has the coordinates (2,0). What is the distance between points C and D? Is ____ u

nits

Mathematics
1 answer:
beks73 [17]3 years ago
3 0

Answer: 5 units

Step-by-step explanation:

Distance = \sqrt{(x_{2 }- x_{1 })^2 + (y_{2 }- y_{1 })^2\\

= \sqrt{(2_ }- (-1)_{ })^2 + (0_{ }- 4_{ })^2

= \sqrt{(2_{ }+ 1_{ })^2 + (-4)^2_

= \sqrt{3^2+(-4)^2}

= \sqrt{9+16}

= \sqrt{25}

= 5 units

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Oksana_A [137]

Answer:

<em>The final price including tax is $41.89</em>

Step-by-step explanation:

The following items are on sale:

Sleeved dress $17.99

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8 0
3 years ago
What are like terms?
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Find dy/dx by differentiating implicitly <br> x^2y+3xy^3-x=3
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6 0
3 years ago
The straight line PQ with P(1,6) and Q(-6, 1). PQ is mapped onto P'Q' by a reflection in the line = 2. What are the coordinates
SSSSS [86.1K]

Answer:

P' = (1,-2)

Step-by-step explanation:

Given

P = (1.6)

Q = (-6,1)

Reflection over: y = 2

Required

Determine the coordinates of P'

From the given coordinates, the y coordinates of P is 6 and the line of reflection is at y = 2

Since we are to reflect over y = 2, only the y coordinate of P will be affected.

The idea behind reflecting a point over a line is to have an equal distance between [the original point & the line of reflection] and [the new point & the line of reflection]

So, what to do is:

First, calculate the difference between the y coordinates of P and the line of reflection.

The y coordinate of P is 6 and the line of reflection is at y = 2.

So, the difference is: 6 -2 = 4

Next, subtract the calculated difference from the line of reflection to get the y coordinate of P'

y coordinate of P' = 2 - 4 = -2

<em>Hence, the coordinate of P' is: (1,-2)</em>

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