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Ahat [919]
3 years ago
10

Point C has the coordinates (-1,4) and point D has the coordinates (2,0). What is the distance between points C and D? Is ____ u

nits

Mathematics
1 answer:
beks73 [17]3 years ago
3 0

Answer: 5 units

Step-by-step explanation:

Distance = \sqrt{(x_{2 }- x_{1 })^2 + (y_{2 }- y_{1 })^2\\

= \sqrt{(2_ }- (-1)_{ })^2 + (0_{ }- 4_{ })^2

= \sqrt{(2_{ }+ 1_{ })^2 + (-4)^2_

= \sqrt{3^2+(-4)^2}

= \sqrt{9+16}

= \sqrt{25}

= 5 units

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Quadrilateral QRST is a square. If the measure of angle RQS is 5x – 15. Find the value of x.
rodikova [14]

angle of RQS = 45 degrees so

5X-15 = 45

5x=60

x = 12

6 0
3 years ago
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Help please, not sure how to do this...​
olga nikolaevna [1]

Answer:

8.38

Step-by-step explanation:

The underlined number is in the hundredths place, so that means that we're going to round there. That means that you look at the number to its right and if it's lower than 5, it stays the same. However, if it's 5 or higher, you round it up. For example, if the number was 8.386, we would round it to 8.39.

5 0
3 years ago
Two subtracted from b is greater than -18
Ber [7]
(b-2)>-18
OR
-18+(b-2)
8 0
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The sum of the components of anything equals the whole thing. Which property/postulate does this statement represent?
IgorC [24]
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5 0
3 years ago
0.3(4-x)=x-1.4 how do you solve this problem?
tresset_1 [31]

Answer:

x = 2.

Step-by-step explanation:

Solve for x:

0.3 (4 - x) = x - 1.4

Expand out terms of the left hand side:

1.2 - 0.3 x = x - 1.4

Subtract x from both sides:

1.2 + (-0.3 x - x) = (x - x) - 1.4

-0.3 x - x = -1.3 x:

-1.3 x + 1.2 = (x - x) - 1.4

x - x = 0:

1.2 - 1.3 x = -1.4

Subtract 1.2` from both sides:

(1.2 - 1.2) - 1.3 x = -1.2 - 1.4

1.2 - 1.2 = 0:

-1.3 x = -1.2 - 1.4

-1.2 - 1.4 = -2.6:

-1.3 x = -2.6

Divide both sides of -1.3 x = -2.6 by -1.3:

(-1.3 x)/(-1.3) = (-2.6)/(-1.3)

(-1.3)/(-1.3) = 1:

x = (-2.6)/(-1.3)

(-2.6)/(-1.3) = 2.:

Answer:  x = 2.

4 0
3 years ago
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