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Liono4ka [1.6K]
3 years ago
15

For a certain font, the scale factor is 1.21 and one of the scale sizes is 1.772.

Mathematics
1 answer:
Igoryamba3 years ago
5 0
The size of the next smaller scale wil about 1.464.

The scale factor represents the change between the different sizes. We multiply by it to increase and divide by it to reduce.

1.772 / 1.21 = 1.464
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(T x 2) - 14 For t=46
o-na [289]

Answer:

78

Step-by-step explanation:

Use PEMDAS for questions like these (Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction) It gives an order in which you should solve the problem. In this case, put 46 instead of T to get (46*2)-14. If we look at PEMDAS, it shows that we need to do what is in the parenthesis first. So, 46x2=92. You get 92-14. Solve that and you get 78

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3 years ago
Help. Algebra word problem
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They will be 170 pounds by the end of the year. 5% of 100 would be 5 so 5% of 200 is half of 5 which is 2.5. 2.5 times 12 will get you 30. 200-30 is 170

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7 0
3 years ago
Can someone help me with this????
Irina-Kira [14]
Angle 5= 46
Angle 7= 46  They are opposite, therefore, they measure the same.
 
If angle 2 is 134 degrees, so is angle 4.
They are parallel to each other, so angle 2 equals to angle 6, angle 4 equals to angle 8.
The sum of the four angles (5, 6, 7, & 8) is 360. The sum of the angle 2 (6) and angle 4 (8) is 268 (134x2).
360-268=92
92/2=46    Angles 5 and 7 are equal to each other, and their sum is 92, then you                    just need to divide 92 by two
                
               I do not know about the signs next to 5 and 7, though. I hope this helped                  you
3 0
4 years ago
Find the fifth term of the geometric sequence whose first term is 81 and whose common ratio is 1/3.(1 point)13
Ludmilka [50]

n^{th}\textit{ term of a geometric sequence} \\\\ a_n=a_1\cdot r^{n-1}\qquad \begin{cases} a_n=n^{th}\ term\\ n=\stackrel{\textit{term position}}{5}\\ a_1=\stackrel{\textit{first term}}{81}\\ r=\stackrel{\textit{common ratio}}{\frac{1}{3}} \end{cases}\implies a_5=81\left( \cfrac{1}{3} \right)^{5-1} \\\\\\ a_5=81\left( \cfrac{1}{3} \right)^4\implies a_5=81\cdot \cfrac{1}{81}\implies a=1

7 0
2 years ago
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borishaifa [10]
2 and 3/5 boxes because 1/5 + 2/5 = 3/5, and 2 + 3/5 = 2 and 3/5
7 0
3 years ago
Read 2 more answers
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