4 years ago

Line CD contains points A (4, 6) and B (−2, 6). What is the slope of the line CD?

2 answers:

5 0

The slope of the line given the points is calculated through the equation,
m = (y2 - y1) / (x2 - x1)
Substituting the known values,
m = (6 - 6) / (-2 - 4) = 0
The slope of the given line is equal to 0 which means that it is a horizontal line.

Elden [556K]4 years ago

3 0

so is it a b c or d?

zero

undefined

positive

negative

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DedPeter [7]

Answer:

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Step-by-step explanation:

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4 0

3 years ago

Simplify the expression.<br><br> 4d+9−d−8

skad [1K]

4d + 9 - d - 8 = (4d - d) + (9 - 8) = d(4 - 1) + 1 = 3d + 1

8 0

4 years ago

Read 2 more answers

Write the slope-intercept form of the equation for the line.

OLEGan [10]

let's use those two endpoints in the line of (-5 , 2) and (5 , -1)

$\bf (\stackrel{x_1}{-5}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{-1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-2}{5-(-5)}\implies \cfrac{-3}{5+5}\implies -\cfrac{3}{10}$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=-\cfrac{3}{10}[x-(-5)]\implies y-2=-\cfrac{3}{10}(x+5) \\\\\\ y-2=-\cfrac{3}{10}x-\cfrac{3}{2}\implies y=-\cfrac{3}{10}x-\cfrac{3}{2}+2\implies y=-\cfrac{3}{10}x+\cfrac{1}{2}$