Answer:
Option 2 - Approximately 24–36 pounds
Step-by-step explanation:
Given : A standard American Eskimo dog has a mean weight of 30 pounds with a standard deviation of 2 pounds. Assuming the weights of standard Eskimo dogs are normally distributed.
To find : What range of weights would 99.7% of the dogs have?
Solution :
The range of 99.7% will lie between the mean ± 3 standard deviations.
We have given,
Mean weight of Eskimo dogs is
Standard deviation of Eskimo dogs is
The range of weights would 99.7% of the dogs have,





Therefore, The range is approximately, 24 - 36 pounds.
So, Option 2 is correct.
Answer:
Naruto and luffy and Goku will kill you.
Step-by-step explanation:
Answer:
A box plot is drawn with end points at 24 and 49.The box extends from 28 to 44 and a vertical line is drawn inside the box at 34.
Step-by-step explanation:
Ordering the data given :
24,28,32,34,40,44,49
We can calculate the 5 number summary required to give the appropriate boxplot that can be produced :
Minimum = 24
Maximum = 49
Median = 1/2(n+1)th term
n = 7
Median = 1/2(8) = 4th term
Median = 34
Lower quartile, Q1 = 1/4(n+1)th term
n = 7
1/4(8) = 2nd term
Q1 = 28
Upper quartile : 3/4(n+1)th term
n = 7
Q3 = 3/4(8) = 6th term
Q3= 44
Answer:
I would say equal to twelve
Step-by-step explanation:
Hope this helps.
Given the function:

Let's find the amplitude and period of the function.
Apply the general cosine function:

Where A is the amplitude.
Comparing both functions, we have:
A = 1
b = 4
Hence, we have:
Amplitude, A = 1
To find the period, we have:

Therefore, the period is = π/2
The graph of the function is shown below:
The parent function of the given function is:

Let's describe the transformation..
Apply the transformation rules for function.
We have:
The transformation that occured from f(x) = cosx to g(x) = cos4x using the rules of transformation can be said to be a horizontal compression.
ANSWER:
Amplitude = 1
Period = π/2
Transformation = horizontal compression.