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2 years ago

Which expression completes the factored form of this quadratic expression? x2 + 4x – 5

1 answer:

5 0

Find factors of -5 that, when added together, will give 4

x² + 4x - 5
x 5
x -1

(x + 5)(x -1)

Using the FOIL method (First, Outside, Inside, Last), we can get the question again.

x(x) = x²
x(-1) = -x
5(x) = 5x
5(-1) = -5

x² - x + 5x - 5
x² + 4x - 5

(x + 5) (x - 1) is your answers

however, i believe it is only asking for one. Therefore, because (x - 1) is a choice, (x - 1) should be your answer

hope this helps

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if you multiply the number by 2 and add 4, then result you get will be the same as three times the number decreased by 7.

liraira [26]

Answer:

Step-by-step explanation:

Let the number be x,

2x+4 = 3x-7

Collect like terms

2x-3x= -4-7

-x =. -11

Multiply both sides by -1

x. =. 11

PLEASE MARK BRAINLIEST.

5 0

2 years ago

A 100-foot rope from the top of a tree house to the ground forms a 45∘ angle of elevation from the ground. How high is the top o

DochEvi [55]

Answer:

The height of tree house is 70.71 feet

Step-by-step explanation:

We are given that A 100-foot rope from the top of a tree house to the ground forms a 45∘ angle of elevation from the ground

Refer the attached figure

Length of rope AC = Hypotenuse =100 feet

The top of a tree house to the ground forms a 45∘ angle of elevation from the ground = $\angle ACB = 45^{\circ}$

We are supposed to find the height of tree house i.e.AB = Perpendicular

So, Using trigonometric ratio

$Sin \theta = \frac{perpendicular}{Hypotenuse}\\Sin 45= \frac{AB}{AC}\\\frac{1}{\sqrt{2}}=\frac{AB}{100}\\100 \times \frac{1}{\sqrt{2}}=AB\\70.71=AB$

Hence The height of tree house is 70.71 feet

8 0

3 years ago

Find the area of figure 1. a -12 units2 b- 14 units2 c- 8 units2 d- 10 units2

Brilliant_brown [7]

Answer:

Step-by-step explanation:

if you look at the chart. it goes up five and has a width of 2. multiply 5 x 2 = you get 10

3 0

2 years ago

Read 2 more answers

Given f(x) and g(x) = f(x) + k, use the graph to determine the value of k.

Slav-nsk [51]

Answer:

find out how many units higher g(x) is compared to f(x).

g(x) is 3 units higher than f(x)

Since the graph is 3 units higher, the value of k must be 3.

Step-by-step explanation:

ok i honestly hope i answerd this correctly because im terrible at reading math

6 0

2 years ago

Consider the following initial value problem, in which an input of large amplitude and short duration has been idealized as a de

Ganezh [65]

Answer:

a. $\mathbf{Y(s) = L \{y(t)\} = \dfrac{7}{s(s+1)}+ \dfrac{e^{-3s}}{s+1}}$

b. $\mathbf{y(t) = \{7e^t + e^3 u (t-3)-7\}e^{-t}}$

Step-by-step explanation:

The initial value problem is given as:

$y' +y = 7+\delta (t-3) \\ \\ y(0)=0$

Applying laplace transformation on the expression $y' +y = 7+\delta (t-3)$

to get $L[{y+y'} ]= L[{7 + \delta (t-3)}]$

$l\{y' \} + L \{y\} = L \{7\} + L \{ \delta (t-3\} \\ \\ sY(s) -y(0) +Y(s) = \dfrac{7}{s}+ e ^{-3s} \\ \\ (s+1) Y(s) -0 = \dfrac{7}{s}+ e^{-3s} \\ \\ \mathbf{Y(s) = L \{y(t)\} = \dfrac{7}{s(s+1)}+ \dfrac{e^{-3s}}{s+1}}$

Taking inverse of Laplace transformation

$y(t) = 7 L^{-1} [ \dfrac{1}{(s+1)}] + L^{-1} [\dfrac{e^{-3s}}{s+1}] \\ \\ y(t) = 7L^{-1} [\dfrac{(s+1)-s}{s(s+1)}] +L^{-1} [\dfrac{e^{-3s}}{s+1}] \\ \\ y(t) = 7L^{-1} [\dfrac{1}{s}-\dfrac{1}{s+1}] + L^{-1}[\dfrac{e^{-3s}}{s+1}] \\ \\ y(t) = 7 [1-e^{-t} ] + L^{-1} [\dfrac{e^{-3s}}{s+1}]$