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3 years ago

If p —> q and q —> r are true conditional statements,

Mathematics

1 answer:

kirill [66]3 years ago

8 0

Answer:

False; this is the law of syllogism.

Step-by-step explanation:

Law of Detachment is:

1) p->q

2) p

------------------------

Conclusion: q

Law of syllogism is:

1) p->q

2) q->r

---------------------

Conclusion: p->r

You might be interested in

The number and frequency of Atlantic hurricanes annually from 1940 through 2007 is shown here:

klio [65]

Answer:

The probability table is shown below.

A Poisson distribution can be used to approximate the model of the number of hurricanes each season.

Step-by-step explanation:

(a)

The formula to compute the probability of an event E is:

$P(E)=\frac{Favorable\ no.\ of\ frequencies}{Total\ NO.\ of\ frequencies}$

Use this formula to compute the probabilities of 0 - 8 hurricanes each season.

The table for the probabilities is shown below.

(b)

Compute the mean number of hurricanes per season as follows:

$E(X)=\frac{\sum x f_{x}}{\sum f_{x}}=\frac{176}{68}= 2.5882\approx2.59$

If the variable X follows a Poisson distribution with parameter λ = 7.56 then the probability function is:

$P(X=x)=\frac{e^{-2.59}(2.59)^{x}}{x!} ;\ x=0, 1, 2,...$

Compute the probability of X = 0 as follows:

$P(X=0)=\frac{e^{-2.59}(2.59)^{0}}{0!} =\frac{0.075\times1}{1}=0.075$

Compute the probability of X = 1 as follows:

$\neq P(X=1)=\frac{e^{-2.59}(2.59)^{1}}{1!} =\frac{0.075\times7.56}{1}=0.1943$

Compute the probabilities for the rest of the values of X in the similar way.

The probabilities are shown in the table.

On comparing the two probability tables, it can be seen that the Poisson distribution can be used to approximate the distribution of the number of hurricanes each season. This is because for every value of X the Poisson probability is approximately equal to the empirical probability.

5 0

3 years ago

Whats the answer to this?

nordsb [41]

Answer:

Option 4) s is greater to or less than 15

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

If 40% of a number is 56. What was the original number

Phantasy [73]

$40\% \ of x = 56 \\ \\ \frac{40}{100}*x=56 \\ \\ x=56: \frac{40}{100} \\ \\ x=56* \frac{100}{40}= \frac{5600}{40}= 140 . \\ \\ \\\\\huge\text{The answer is x=140 !}$

4 0

2 years ago

What is the quotient (x3 – 3x2 + 5x – 3) ÷ (x – 1)?

NeTakaya

Answer:

The quotient of the expression will be (x² - 2x + 3).

Step-by-step explanation:

The given expression is (x³ - 3x² + 5x - 3) ÷ (x - 1)

Now we will use the synthetic division method to solve this question.

We will note down the coefficient of the expression as below

x³ x² x constant

1 (-3) 5 -3

1 1 (1×1-3)=(-2) [1×(-2)+5]=3 (1×3-3)=0

Therefore (x -1) is a perfect zero factor.

Now we can easily say that coefficient of the expression is [1.x² + (-2)x + (3)]

and remainder is 0.

Or in more simplified way coefficient of the expression will be

(x² -2x + 3).

8 0

3 years ago

Read 2 more answers

g A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 48.0 and 5

Kisachek [45]

Answer: 0.025

Step-by-step explanation:

Given : A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between interval : [48.0 minutes, 53.0 minutes]

Let x be the lengths of her classes that are uniformly distributed between interval : [48.0 minutes, 53.0 minutes].

The probability density function for the given situation :-

$f(x)}=\dfrac{1}{55-45}=\dfrac{1}{10}$

The probability that a given class period runs between 51.25 and 51.5 minutes is given by :-

$P(51.25$

Hence, the probability that a given class period runs between 51.25 and 51.5 minutes is 0.025 .

7 0

3 years ago