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ValentinkaMS [17]
3 years ago
12

Examine rectangle JKLM, shown below.

Mathematics
1 answer:
IRISSAK [1]3 years ago
5 0

Answer:

NM = 8

Step-by-step explanation:

Given rectangle JKLM

JN = x + 3 and JL = 3x + 1

JN = 1/2JL as diagonals bisect each other and N is the midpoint of JL.

Substitute and solve for x:

x + 3 = 1/2(3x + 1)

2x + 6 = 3x + 1

3x - 2x = 6 - 1

x = 5

Find JN

JN = 5 + 3 = 8

Looking at the options, we see that

NM = JN = 8

Correct option is A

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Answer:

64√2 or 64 StartRoot 2 EndRoot

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Therefore, the two legs are x and the hypotenuse is x√2.  x√2=128 because the question says that the hypotenuse is 128.  Solve for x by dividing both sides by √2.  X=128/√2.  You rationalize it by multiplying the numberator and denominator of the fraction by √2.  √2*√2= 2.

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Answer:

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Step-by-step explanation:

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