The team won 4 gold medals, 4 silver medals and 10 bronze medals.
Step-by-step explanation:
Given,
Total medals won = 18
Ratio of gold, silver and bronze = 2:2:5
Let,
x be the original number.
Therefore,
Gold medals = 2x
Silver medals = 2x
Bronze medals = 5x
According to given statement;
Dividing both sides by 9
Gold medals = 2x = 2(2) = 4
Silver medals = 2x = 2(2) = 4
Bronze medals = 5x = 5(2) = 10
The team won 4 gold medals, 4 silver medals and 10 bronze medals.
Keywords: ratio, division
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Answer:
Kindly check explanation
Step-by-step explanation:
Given the data :
Technician __Shutdown
Taylor, T___4
Rousche, R _ 3
Hurley, H__ 3
Huang, Hu___2
Gupta, ___ 5
The Numbe of samples of 2 possible from the 5 technicians :
We use combination :
nCr = n! ÷ (n-r)!r!
5C2 = 5!(3!)2!
5C2 = (5*4)/2 = 10
POSSIBLE COMBINATIONS :
TR, TH, THu, TG, RH, RHu, RG , HHu, HG, HuG
Sample means :
TR = (4+3)/2 = 3.5
TH = (4+3)/2 = 3.5
THu = (4+2) = 6/2 = 3
TG = (4 + 5) = 9/2 = 4.5
RH = (3+3) = 6/2 = 3
RHu = (3+2) /2 = 2.5
RG = (3 + 5) = 8/2 = 4
HHu = (3+2) = 2.5
HG = (3+5) = 8/2 = 4
HuG = (2+5) / 2 = 3.5
Mean of sample mean (3.5+3.5+3+4.5+3+2.5+4+2.5+4+3.5) / 10 = 3.4
Population mean :
(4 + 3 + 3 + 2 + 5) / 5 = 17 /5 = 3.4
Population Mean and mean of sample means are the same.
This distribution should be approximately normal.
8 maybe? I’m really not sure but I just did 5x1.6
Step-by-step explanation:
terminate as it had already been simplify
Answer:
Step-by-step explanation:
b.
an=an-1+3
C.
when x=15
y=3×15-2=45-2=43
a15=43
