Given end points of diameter,
(x1,y1)=(-3,-4)
(x2,y2)=(0,0)
Now,
the equation of circle is,
(x-x1)(x-x2)+(y-y1)(y-y2)=0
or, (x+3)(x-0)+(y+4)(y-0)=0
or, x^2 +3x +y^2 +4y =0
or, x^2 +y^2 +3x + 4y=0
which is in the form of x^2 +y^2 +2gx +2fy + c=0
where,
g=3/2
h=2
c=0
Now,
Answer:you got this
Step-by-step explanation:
Answer:
31 + 4y
Step-by-step explanation:
4(6+y)+7
Expand the brackets.
24+4y+7
Rearrange.
4y + 24 + 7
Add the like terms.
4y + 31
<h3>Answer:</h3><h3>The equation for the slope of a line, given two coordinate points, (x1,y1) , (x2,y2), is (y2-y1)/(x2-x1) </h3><h3> So we get slope = (1-(-5)) / (4-1) = 6/3 = 2</h3><h3>A is your correct answer.</h3>
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