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klemol [59]
3 years ago
6

Find and simplify the difference quotient of the​ form,

%7D%20%2C%20h%5Cneq%200" id="TexFormula1" title="\frac{f(x+h)-f(x)}{h} , h\neq 0" alt="\frac{f(x+h)-f(x)}{h} , h\neq 0" align="absmiddle" class="latex-formula">
f(x)=-10x+9
\frac{f(x+h)-f(x)}{h} =
Mathematics
1 answer:
Anastasy [175]3 years ago
7 0

With f(x)=-10x+9, we have

f(x+h) = -10(x+h) + 9 = -10x + 9 - 10h

Then the difference quotient is

\dfrac{f(x+h)-f(x)}h = \dfrac{(-10x+9-10h)-(-10x+9)}h = \dfrac{-10h}h = -10

since <em>h</em> ≠ 0.

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Answer:

y=-\dfrac{1}{2}(x+4)^2-1

Step-by-step explanation:

Vertex form:  y=a(x-h)^2+k  

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Substitute given values into the formula to find a:

\implies -3=a((-2)-(-4))^2+(-1)

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6 0
2 years ago
Read 2 more answers
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