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Katyanochek1 [597]
4 years ago
13

Can someone please help?

Mathematics
1 answer:
liberstina [14]4 years ago
8 0

Answer:

hey

Step-by-step explanation:

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5 x (h + 3) for h = 7 dose anyone know the answer to this?
-BARSIC- [3]

Answer:

50

Step-by-step explanation:

5* ( 7+3)

5* 10

50.

.so the answer is 50

6 0
3 years ago
Read 2 more answers
Baruch college has 1000 students in the spring of 2018. 30 percent of the students use the gym twice per week, 70 percent of the
astraxan [27]

Answer:

The average per week flow rate of students to the gym is <u>2700</u>.

Step-by-step explanation:

Given:

Baruch college has 1000 students in the spring of 2018. 30 percent of the students use the gym twice per week, 70 percent of the students use the gym three times a week.

Now, to find the average per week flow rate of students to the gym.

Total number of students = 1000.

So, 30 percent of the students use the gym twice per week:

30\%\ of\ 1000\times 2\\\\=\frac{30}{100}\times 1000\times 2\\\\=0.30\times 1000\times 2\\\\=600.

Now, 70 percent of the students use the gym three times a week:

70\%\ of\ 1000\times 3\\\\=\frac{70}{100} \times 1000\times 3\\\\=0.70\times 1000\times 3\\\\=2100.

Now, to get the average per week flow rate of students to the gym by adding 30 percent of the students use the gym twice per week and 70 percent of the students use the gym three times a week:

600+2100

=2700.

Therefore, the average per week flow rate of students to the gym is 2700.

3 0
3 years ago
What is 1 2/3 - 2 1/3?
Zarrin [17]

Answer:

-1/3

Step-by-step explanation:

3 0
3 years ago
Solve for x.<br> 7y-6y-19=13
Hitman42 [59]

Answer:

Y=32

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
In problem solve the given differential equation by underdetermined coefficients y''-2y+y=xe^x
Alexus [3.1K]

Answer:

Solution is y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}

Step-by-step explanation:

Given Differential Equation,

y"-2y'+y=xe^x ...............(1)

We need to solve the given differential equations using undetermined coefficients.

Let the solution of the given differential equation is made up of two parts. one complimentary solution and one is particular solution.

\implies\:y(x)=y_c(x)+y_p(x)

For Complimentary solution,

Auxiliary equation is as follows

m² - 2m + 1 = 0

( m - 1 )² = 0

m = 1 , 1

So,

y_c(x)=C_1e^x+c_2xe^x

Now for particular solution,

let y_p(x)=Ax^3e^x

y'=Ax^3e^x+3Ax^2e^x

y"=Ax^3e^x+6Ax^2e^x+6Axe^x

Now putting these values in (1), we get

Ax^3e^x+6Ae^2e^x+6Axe^x-2(Ax^3e^x+3Ax^2e^x)+Ax^3e^x=xe^x

Ax^3e^x+6Ae^2e^x+6Axe^x-2Ax^3e^x-6Ax^2e^x+Ax^3e^x=xe^x

6Axe^x=xe^x

6A=1

A=\frac{1}{6}

\implies\:y_p(x)=\frac{x^3e^x}{6}

Therefore, Solution is y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}

8 0
4 years ago
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