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3 years ago

Sana reaches her office 20 minutes late by

Mathematics

1 answer:

iris [78.8K]3 years ago

4 0

Uh....I don’t think you finished the question yet lol

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How many steel rods are in a staircase frame with 12 steps?

kolbaska11 [484]

180 steel rods to be exact

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3 years ago

HELPPPPPPP PLSSS answer the question

Yuliya22 [10]

Answer:

i need help with something like that aswell

Step-by-step explanation:

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3 years ago

If f(x) and its inverse function, f^-1(x), are both plotted on the same coordinate plane, where is their point of intersection?

zloy xaker [14]

Answer:

Step-by-step explanation:

Their point of intersection, assuming there is one, will be somewhere on the line y = x. This line, y = x, is the line of symmetry between a function and its inverse. So if the two do in fact intersect, it will be at some point on that line

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3 years ago

Victoria spent one-fourth of her birthday money on clothes. She received another $25 a week later. If she has a total of $70 now

tia_tia [17]

Answer:

she had $60 before she went for shopping

Step-by-step explanation:

PLZ MARK BRAINLIEST

Let x represent the amount of money that Victoria had before she went for shopping.

Victoria spent one-fourth or her birthday money on clothes. It means that the amount she spent on shopping is 1/4 × x = x/4. Amount that she was having left would be x - x/4 = 3x/4

She received another 25$ a week later. The amount that she is having at this point will be 3x/4 + 25

If she has a total of 70$ now, it means that

3x/4 + 25 = 70

Multiplying through by 4

3x + 100 = 280

3x ,= 280 - 100 = 180

x = 180/3 = 60

3 0

3 years ago

Evaluate the surface integral ModifyingBelow Integral from nothing to nothing Integral from nothing to nothing With Upper S f (x

kykrilka [37]

Parameterize $S$ by

$\vec s(u,v)=6\cos u\sin v\,\vec\imath+6\sin u\sin v\,\vec\jmath+6\cos v\,\vec k$

with $0\le u\le2\pi$ and $0\le v\le\frac\pi2$ . Take a normal vector to $S$ ,

$\dfrac{\partial\vec s}{\partial v}\times\dfrac{\partial\vec s}{\partial u}=36\cos u\sin^2v\,\vec\imath+36\sin u\sin^2v\,\vec\jmath+36\cos v\sin v\,\vec k$

which has norm

$\left\|\dfrac{\partial\vec s}{\partial v}\times\dfrac{\partial\vec s}{\partial u}\right\|=36\sin v$

Then the integral of $f(x,y,z)=x^2+y^2$ over $S$ is

$\displaystyle\iint_Sx^2+y^2\,\mathrm dS=\iint_S\left((6\cos u\sin v)^2+(6\sin u\sin v)^2\right)\left\|\frac{\partial\vec s}{\partial v}\times\frac{\partial\vec s}{\partial u}\right\|\,\mathrm du\,\mathrm dv$

$=\displaystyle36^2\int_0^{\pi/2}\int_0^{2\pi}\sin^3v\,\mathrm du\,\mathrm dv=\boxed{1728\pi}$

6 0

4 years ago

Sana reaches her office 20 minutes late by​

Sana reaches her office 20 minutes late by