All u have to do is plug in the values
68) -(4q) = -(4*-3) =-4*3= -12
70) 5P-6= (5*5)-6 =25-6= 19
72) 7q-7p= 7(-3)-7(5) = -21-35= -56
74)2q/(4p) = 2(-3)/4(5)= -6/20= -3/10
I think that’s the answer
Let C be the center of the circle. The measure of arc VSU is 
, so the measure of the minor arc VU is 
. The central angle VCU also has measure 
.
Triangle CUV is isosceles, so the angles CVU and CUV are congruent. The interior angles of any triangle are supplementary (they add to 180 degrees) so
UT is tangent to the circle, so CU is perpendicular to UT. Angles CUV and VUT are complementary, so
So finally,
degrees.
triangle on right is the same as the triangle on the left
use pythagorean theorem
hypotenuse will give to the sides of the rectangle
a^2 + b^2 = hypotenuse squared
10.4^2 = 108.16
15.3^2 = 234.09
342.25 = hypotenuse squared
take the square root in both sides
hypotenuse = the square root of 342.25 =
18.5
add up the areas of the 2 triangles and rectangle
triangle area is 1/2 times 10.4 times 15.3 =
79.56
2 triangles areas are 159.12
rectangle area is 18.5 × 7 = 129.5
159.12 + 129.5 = 288.62
answer 1 = 288.62
second question:
to get 1 side take the
square root of 702.25 which is
26.5
to get the perimeter
multiply 26.5 by 4 which is
106
answer 2 is choice B 106
