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Ksenya-84 [330]
3 years ago
14

I NEED HELP PLEASE, THANKS! :)

Mathematics
1 answer:
Maksim231197 [3]3 years ago
4 0

Answer:

Option B

Step-by-step explanation:

First identify which options are a match for the hyperbola with a foci of (- 12, 6) and ( 6, 6 ). If there is only one, we can claim that that is the solution. Otherwise we would have to take the vertices into account,

The first option can be eliminated as it is present with a decimal in the denominator, indicating that the foci should also be a decimal. However, the foci of this option should be valuable to us -

\left(h+c,\:k\right),\:\left(h-c,\:k\right),\\\left(-3+c,\:6\right),\:\left(-3-c,\:6\right),\\c = ( About ) 3.6,\\\\Foci = \left(0.55808 ,\:6\right),\:\left(-6.55808,\:6\right)

The second option squares the denominators of the first option, so the foci should be the following -

Foci = ( - 12, 6 ), ( 6, 6 )

Which is the given! The rest of the options are similar to this second option, but are altered, thus don't have the same foci,

<u><em>Solution = Option B</em></u>

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b. 6.2×10³ × 5.2×10⁶ ≈ 6×5×10⁹ = 3×10¹⁰ approximately

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As in part B, either approximation is adequate for most purposes, as the difference from the actual value is less than .3%.

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