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Ksenya-84 [330]
3 years ago
14

I NEED HELP PLEASE, THANKS! :)

Mathematics
1 answer:
Maksim231197 [3]3 years ago
4 0

Answer:

Option B

Step-by-step explanation:

First identify which options are a match for the hyperbola with a foci of (- 12, 6) and ( 6, 6 ). If there is only one, we can claim that that is the solution. Otherwise we would have to take the vertices into account,

The first option can be eliminated as it is present with a decimal in the denominator, indicating that the foci should also be a decimal. However, the foci of this option should be valuable to us -

\left(h+c,\:k\right),\:\left(h-c,\:k\right),\\\left(-3+c,\:6\right),\:\left(-3-c,\:6\right),\\c = ( About ) 3.6,\\\\Foci = \left(0.55808 ,\:6\right),\:\left(-6.55808,\:6\right)

The second option squares the denominators of the first option, so the foci should be the following -

Foci = ( - 12, 6 ), ( 6, 6 )

Which is the given! The rest of the options are similar to this second option, but are altered, thus don't have the same foci,

<u><em>Solution = Option B</em></u>

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Answer:

She worked 12 hours for the week

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Which expressions are completely factored?
amm1812

The only expressions that are correctly factored are;

A) 16a⁵ - 20a³ = 4a³(4a² - 5)

B) 24a⁴ + 18 = 6(4a⁴ + 3)

C) 12a³  + 8a = 4a(3a² + 2)

D) 30a⁶ - 24a² = 3a²(10a⁴ - 8)

<h3>How to factorize equations?</h3>

1) 16a⁵ - 20a³

To factorize this, we will have to get out the common factor first. The common factor is 4a³. Thus, we now have;

4a³(4a² - 5)

2) 24a⁴ + 18

To factorize this, we will have to get out the common factor first. The common factor is 6. Thus, we now have;

6(4a⁴ + 3)

3) 12a³  + 8a

To factorize this, we will have to get out the common factor first. The common factor is 4a. Thus, we now have;

4a(3a² + 2)

4) 30a⁶ - 24a²

To factorize this, we will have to get out the common factor first. The common factor is 3a². Thus, we now have;

3a²(10a⁴ - 8)

Read more about factorization of equations at; brainly.com/question/723406

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