Answer:
$80
Step-by-step explanation:
From the question, we are given The simple interest formula as I = Prt,
where l = simple interest on an amount= $40
t= years=5years
at a rate r= 10%
The rate= 10/100= 0.1
Then since we are looking for P, we can make P subject of formula from this expression;
I = Prt
P=I/rt
P= 40/(0.1 ×5)
P= 40/0.5
P= 80
therefore, the amount of money p that is needed is $80
Answer:
according to the question value got less 12% each year
first of all the 12% of 29000$ = 29000÷100×12= 3480 $
in one year truck value deprecates 3480$
in 10 years it will 3480$×10 =34800$
now truck cost will be = 29000-34800$= -5000$
First way: x * 1.05
This computes directly what 105% of x will be.
Second way: x + (x * 0.05)
This takes x (which is 100%) and adds 5% of x to it.
Answer:
g(x) = (f-x)
Step-by-step explanation:
It's relection across the y axis
==> g(x) = (f-x)