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Evgen [1.6K]
3 years ago
10

What is the measure of angle c in degrees? * 150 30 90 60

Mathematics
1 answer:
Dmitry [639]3 years ago
4 0

Answer:

Option (2)

Step-by-step explanation:

Measure of angle formed by two tangents from a point outside the circleis half the difference of the measures of the intercepted arcs.

From the figure attached,

m∠C = \frac{1}{2}[m(\text{major arc AB})-m(\text{minor arc AB)}]

        = \frac{1}{2}[(360-m\widehat{AB})-m(\widehat{AB})]

        = \frac{1}{2}[360-2m(\widehat{AB})]

        = 180-m\widehat{AB}

        = 180 - 150

        = 30°

Therefore, measure of angle C will be 30°.

Option (2) is the answer.

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25 points
lbvjy [14]

Answer:

unit_4_study_guide_solutions.pdf

Step-by-step explanation:

This link is a study guide, and on the LAST PAGE it has the answer to your question!

4 0
3 years ago
Which of the following is not a prime factor?
Liono4ka [1.6K]
63 is the answer to your problem. Hope this helps!
8 0
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One-half the sum of x,y, and z
BabaBlast [244]
The keyword is "sum" which tells you x, y, and z are being added. One half of the sum means that the sum of the three numbers is going to be divided by 2.

x + y + z
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3 0
3 years ago
Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5
givi [52]
<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]                            X=\left[\begin{array}{c}x\\y\end{array}\right]

and          B= \left[\begin{array}{c}11\\5\end{array}\right]

∴AX=B

adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]

A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6

∴A^{-1} =\frac{adj A}{|A|}

So,A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}

A^{-1} ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}

X =A^{-1}\times B

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c}  {6}\\  {11} \end{array}\right]}

∴ x= 6 and y = 11

The required solution is x = 6 and y = 11

7 0
3 years ago
I need help with this
Angelina_Jolie [31]
Answer: 256

F(8)=512- 768
F(8)= 256
Hopes this helps
3 0
2 years ago
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