Question

Help someone please!! Ty

Answer 1

Answer:

Option (B)

Step-by-step explanation:

Let the five distinct positive integers are a, b, c, d, e.

Average of these five integers is 20.

$\frac{a+b+c+d+e}{5}=20$

a + b + c + d + e = 100

If these integers are in the increasing order,

Median of these integers 'c' = 12

If the sum of d and e is the largest then the sum of a and b will be the smallest.

Therefore, the smallest positive integers a and b will be,

a = 1 and b = 2

1 + 2 + 12 + d + e = 100

15 + d + e = 100

d + e = 100 - 15

d + e = 85

Since d will be greater than the median c,

d > c

d > 12

For the largest value of integer 'e', value of 'd' will be minimum.

The least value of d will be = 13

Then, 13 + e = 85

e = 85 - 13

e = 72

{a, b, c, d, e} = {1, 2, 12, 13, 72}

Therefore, the largest possible number is this set will be 72.

Option (B) will be the answer.