Question

A city Council consist of six democrats and eight Republicans if a committee of six people is selected find the probability of selecting 2 democrats 4 Republicans

Answer 1

Answer:

The probability of selecting three Democrats and two Republicans is 0.349

Step-by-step explanation:

Given:

The Number of Democrats = 6

The Number of Republicans = 8

To Find:

Probability of selecting 2 Democrats and 4 Republicans. = ?

Solution:

we have to select a committee of 6 people

Now the probability of selecting 2 Democrats and 4 Republicans.

 =>$\frac{\mathrm{P}(\text { Selecting two Democrats }) \cdot \mathrm{P}(\text { Selecting four Republicans })}{\mathrm{P}(\text { Selecting } 6 \text { member from total } 14)}$

=>$\frac{C(6,2) \cdot C(8,4)}{C(14,6)}$

=>$\frac{ 6 C_{2 } \cdot 8 C_{4}}{14 C_{6}}$

=>$\frac{15\cdot 70}{3003}$

=>$\frac{1050}{3003}$

=>0.349