Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to

sq. units.
To solve this inequality, you need to isolate the value of u. To do this, divide both sides by -2. When you do this, keep in mind that when you divide or multiply both sides by a negative in an inequality, you MUST flip the sign, so your answer would be -8 < u or u > -8.
Answer:
1 x 3 x 1 = 3
Step-by-step explanation: