What is the equation of the trend line?

Mathematics

2 answers:

Soloha48 [4]3 years ago

8 0

Answer:

$N=-2M+110$

Step-by-step explanation:

we know that

The equation of the line in slope-intercept form is equal to

$N=mM+b$

where

m is the slope of the line

b is the N-intercept

In this problem we have

$b=110$

Find the slope

Let

$A(20,70),B(0.110)$

$m=(110-70)/(0-20)=-2$

substitute the values

$N=-2M+110$

mariarad [96]3 years ago

6 0

Answer:

N = -2 M + 110

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The fountain is made up of two semicircles and a quarter circle. Find the perimeter and the area of the fountain. Round the peri

Andrej [43]

FOUND THE COMPLETE QUESTION IN ANOTHER SOURCE.ATTACHED IMAGE.
For this case what we have is the following:
For the two semicircles we can model it as a complete circle.
We have to then:

Perimeter:
P = 2 * pi * r
or
P = pi * d
Where,
r = radius
d = diameter
Therefore the perimeter is:
P = 10 * pi
For the largest circle we have:
radius = 10
Perimeter:
P '= 2pi10
P '= 20pi
1/4 since 1/4 circle:
P '' = 20pi / 4 = 5pi
Then, the total perimeter of the source is:
Pt = P + P '' = 10pi + 5pi = 15pi
Pt = 15 * (3.141592)
Pt = 47.1239
round
Pt = 47.1 ft

Area:
The total area will be:
A = A (two semicircles) + A (quarter big circle)
A = (pi / 4) * (d ^ 2) + (1/4) * pi * r ^ 2
A = (pi / 4) * ((10) ^ 2) + (1/4) * pi * (5) ^ 2
A = 98.17477042 feet ^ 2
Round:
A = 98.2 feet ^ 2

Answer:
Perimeter of the source:
Pt = 47.1 ft
Area of the source:
A = 98.2 feet ^ 2