LCD (1/7, 14/7, 12/13, 5/6)
LCM = (7, 7, 13, 6)
= 2 * 3 * 7 * 13
= 546
1/7 = 78/546
14/7 = 1092/546
12/13 = 504/546
5/6 = 455/546
Calculation:
1/7 + 14/7
= 1 + 14/7
= 15/7
The common denominator you can calculate as the least common multiple of the both denominators: LCM (7, 7) = 7
Add:
15/7 + 12/13
= 15 . 13/7. 13 + 12 . 7/13 . 7
= 195/91 + 84/91
= 195 + 84/91
= 279/91
The common denominator you can calculate as the least common multiple of the both denominators: LCM (7, 13) = 91
Add:
279/91 + 5/6
= 279 . 6/91 . 6 + 5 . 91/6. 91
= 1674/546 + 455/546
= 1674 + 455/546
= 2129/546
The common denominator you can calculate as the least common multiple of the both denominators: LCM (91, 6) = 546
Hence, 546 is the LCM/LCD of (1/7, 14/17, 13/13, 5/6).
Hope that helps!!!!!!
The equation of the parabolas given will be found as follows:
a] general form of the parabolas is:
y=k(ax^2+bx+c)
taking to points form the first graph say (2,-2) (3,2), thus
y=k(x-2)(x-3)
y=k(x^2-5x+6)
taking another point (-1,5)
5=k((-1)^2-5(-1)+6)
5=k(1+5+6)
5=12k
k=5/12
thus the equation will be:
y=5/12(x^2-5x+6)
b] Using the vertex form of the quadratic equations:
y=a(x-h)^2+k
where (h,k) is the vertex
from the graph, the vertex is hence: (-2,1)
thus the equation will be:
y=a(x+2)^2+1
taking the point say (0,3) and solving for a
3=a(0+2)^2+1
3=4a+1
a=1/2
hence the equation will be:
y=1/2(x+2)^2+1
I don't know if that is factor-able. It looks like you could just subtract and get 64t. which would lead to the answer being zero since you divide by zero when isolating the variable t.
Answer:
X = 4
Step-by-step explanation:
-2 times any positive is a negative
X also can't be a negative
so -2 times 4 = -8
Yes, you would get 3 3/4.<span><span>
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