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Anna [14]
3 years ago
11

If anybody now this pls help my homework due TOMORROW

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
6 0

Answer:

<u><em>Part A:</em></u> D. y = (x + 1)(x+3)\\

<u><em>Part B:</em></u> C. 3x(x-3) = 0\\

Step-by-step explanation:

For part A) we just have to plug in 0 for x and solve for y until we find the equation that says 3 is the value for y when x is 0. For purposes of speeding up the process the correct answer is D. I will show how to check for it now.

The equation: y = (x + 1)(x+3)

Now plug in 0 for x.

y = (0 + 1)(0+3)\\

Now solve.

y = (1)(3)

y = 3

This proves that this is the correct answer.

For part B) we just have to plug in the give values for x separately and check for each value of x that it equals 0. For the purpose of speeding up the process the correct answer is C. I will show how to check for it now.

The equation: 3x(x-3) = 0

Now plug in x for 0 and solve:

3* 0 (0-3) = 0\\

0(-3) = 0\\

0 =0\\

This equation is true, now we check for the other value of x, 3.

3*3(3-3) = 0\\

9(0) = 0\\

0 =0\\

This is also true so that means this is the correct answer.

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Answer:

The answer is q=-2.

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6 0
3 years ago
I need help urgent plz someone help me solved this problem! Can someone plz help I’m giving you 10 points! I need help plz help
VMariaS [17]

Answer: a) 8.779 years

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<u>Step-by-step explanation:</u>

a)

A=P\bigg(1+\dfrac{r}{n}\bigg)^{nt}

  • A: accumulated amount (balance)
  • P: principal amount (original/initial investment)
  • r: interest rate (convert to a decimal)
  • n: number of times compounded per year
  • t: number of years

Given: A = 1800, P = 900, r = 8% = 0.08, n = 3, t = unknown

1800=900\bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\2=\bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\ln\ 2=ln \bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\ln\ 2=3t\ ln\bigg(1+\dfrac{0.08}{3}\bigg)\\\\\\\dfrac{ln\ 2}{3\ ln\bigg(1+\dfrac{0.08}{3}\bigg)}=t\\\\\\\large\boxed{8.779=t}

b)  

A=Pe^{rt}

1800=900e^{0.08t}\\\\\\2=e^{0.08t}\\\\\\ln\ 2=0.08t\\\\\\\dfrac{ln\ 2}{0.08}=t\\\\\\\large\boxed{8.664=t}

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