Do the results support or contradict the common belief that the mean body temperature is 98.6degreesF? A. The results contradic
t the belief that the mean body temperature is 98.6degreesF because both the mean and the median are less than 98.6degreesF. B. The results are inconclusive because the median body temperature is not equal to 98.6degreesF while the mean is approximately equal to 98.6degreesF. C. The results are inconclusive because the mean body temperature is not equal to 98.6degreesF while the median is approximately equal to 98.6degreesF. D. The results support the belief that the mean body temperature is 98.6degreesF because both the mean and the median are equal to 98.6degreesF
1 answer:
Answer:
A. The results contradict the belief that the mean body temperature is 98.6 °F because both the mean and the median are less than 98.6 °F.
Step-by-step explanation:
Assume the temperature data were those in the table below.
You would have calculated that
Mean = 97.9 °F
Median = 97.9 °F
These observations contradict the belief that the mean body temperature is 98.6 °F.
A 2017 study found the mean oral temperature of more than 35 000 British patients was 97.9 °F.
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Since ∠C = 120° and ∠A + ∠B + ∠C = 180°, then ∠A = 30° and ∠B = 30°
Next, look at ΔADB. ∠A + ∠D + ∠B = 180°, so ∠A + 90° + 30° = 180° ⇒ ∠A = 30°
Now look at ΔADC. Since ∠A = 30° in ΔACB, and ∠A = 60° in ΔADB, then ∠A = 30° in ΔADC <em>per angle addition postulate.</em>
Now that we have shown that ΔADB and ΔADC are 30-60-90 triangles, we can use that formula to calculate the side lengths.
CD = 4 cm (given) so AC = 2(4 cm) = 8 cm
Since AC ≅ BC, then BC = 8 cm. Therefore, BD = 4 + 8 = 12 <em>by segment addition postulate.</em>
Lastly, look at ΔBHD. Since ∠B = 30° and ∠H = 90°, then ∠D = 60°. So, ΔBHD is also a 30-60-90 triangle.
BD = 12 cm, so HD = = 6 cm
Answer: 6 cm