<span>the particle's initial position is at t=0, x = 0 - 0 + 4 = 4m
velocity is rate of change of displacement = dx/dt = d(t^3 - 9t^2 +4)/dt
= 3t^2 - 18t
acceleration is rate of change of velocity = d(3t^2 -18t)/dt
= 6t - 18
</span><span>the particle is stationary when velocity = 0, so 3t^2 - 18t =0
</span>3t*(t - 6) = 0
t = 0 or t = 6s
acceleration = 6t - 18 = 0
t = 3s
at t = 3s, velocity = 3(3^2) -18*3 = -27m/s
displacement = 3^3 - 9*3^2 +4 = -50m
This is a linear function. you can list out a group of domains or x, then you will get outcomes, which will be your range
Answer:
y=-5/14x-3/2
Step-by-step explanation: Thats the equation
I really hope this answer make sense for you
The code is 200 because they went under the sea to get the key to work.
Answer:
(0,1) and (5,32)
Step-by-step explanation:
Edg.2020