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tangare [24]
3 years ago
9

Determine if the function f(x)=x+4 is increasing or decreasing on the interval of 2≤x≤5. Justify your answer.

Mathematics
1 answer:
Rudik [331]3 years ago
7 0

Step-by-step explanation:

Given

The function is f(x)=x+4

for x_2>x_1, we will check the values of f(x_1) and f(x_2)

Take 3 and 4

f(4)=4+4\\f(4)=8

Similarly,

f(3)=3+4\\f(3)=7

Thus, f(4)>f(3)

Also, f'(x) is 1 i.e. a constant value. So, the function is increasing linearly for the given interval.

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SHOW YOUR WORK! MARK THE BRAINIEST!
avanturin [10]

Answer:

These are the steps to the problem that you are trying to solve. hope it's useful

8 0
3 years ago
Please help!
Salsk061 [2.6K]
VK = VY+YK by the segment addition postulate. Basically adding two segments along a straight line forms a longer segment. In this case, VY and YK combine to form VK

Since VK = x and VY = 22, this means...
VK = VY+YK 
x = 22+YK 
x-22 = YK
YK = x-22

-----------------------------------------------------

Notice the arc marks where the point T is located. These markings tell us that the two angles VTY and YTK are congruent angles. Because of this, we can use the angle bisector theorem which says that the ratio of the corresponding sides are congruent.

In short, we can form this ratio
VT/VY = KT/KY
which is the ratio of the side adjacent to the angle, to the side opposite the angle

Plug in the given values and solve for x
VT/VY = KT/KY
77/22 = 87.5/(x-22)
77(x-22) = 22*87.5
77(x-22) = 1925
77x-77*22 = 1925
77x-1694 = 1925
77x = 1925+1694
77x = 3619
x = 3619/77
x = 47

Answer: 47
5 0
3 years ago
Brad has $39. The daisies are $1 each and the roses are $3 each. He buys 3 more daisies than roses. How much did the roses cost?
Lesechka [4]

How many daisies did he buy

5 0
3 years ago
Read 2 more answers
Select the equation of the line that passes through the .5,7 and is perpendicular to the line x equals 4
lions [1.4K]
Hello!

To be perpendicular to x = 4, the line must be y = something. This eliminates answer choices #2 and #4. Also, to pass through the point (.5, 7), the line must be y = 7.

So answer choice #3.

Hope this helps!! Let me know if you have ANY questions.
8 0
3 years ago
Lim x—&gt; -2 <br> sqrt(3x+10) -2/ x+2
snow_lady [41]

\displaystyle\lim_{x\to-2}\frac{\sqrt{3x+10}-2}{x+2}

Rationalize the numerator:

\dfrac{\sqrt{3x+10}-2}{x+2}\cdot\dfrac{\sqrt{3x+10}+2}{\sqrt{3x+10}+2}=\dfrac{(3x+10)-4}{(x+2)(\sqrt{3x+10}+2)}=\dfrac3{\sqrt{3x+10}+2}

where the x+2 factors in the numerator and denominator cancel. Then the limit is

\displaystyle\lim_{x\to-2}\frac{\sqrt{3x+10}-2}{x+2}=\lim_{x\to-2}\frac3{\sqrt{3x+10}+2}=\frac3{\sqrt4+2}=\boxed{\frac34}

8 0
3 years ago
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