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Artemon [7]
3 years ago
14

The water height of a pool is determined by 8g2 + 3g - 4, the rate that the pool is filled, and 9g2 - 2g - 5, the rate that wate

r leaves the pool, where g represents the number of gallons entering or leaving the pool per minute.
Answer the folowing questions:

A. Write an expression that determines the height of the water in the pool.

B. What will be the height of the water if g = 1, 2, 3, and 4?

C. To the nearest tenth, at which value for g will the water reach its greatest height? explain.

Please i need help i need to turn this in for tomorrow!
Mathematics
2 answers:
Juliette [100K]3 years ago
8 0

Part A

From the question, we know that

Rate at which pool is filled = 8g² + 3g - 4

Rate at which water leaves the pool = 9g² - 2g - 5

Hence, height of the pool would be = Rate at which pool is filled - Rate at which water leaves the pool

⇒ Height of the pool = 8g² + 3g - 4 - (9g² - 2g - 5)

⇒ Height of the pool = -g² + 5g + 1

Part B

Let water height be H

H (g) = -g² + 5g + 1

When g=1, H(1) = -(1)² + 5 (1) + 1 = 5 units

When g=2, H(2) = -(2)² + 5 (2) + 1 = -4+11 = 7 units

When g=3, H(3) = -(3)² + 5 (3) + 1 = -9+16 = 7 units

When g=4, H(4) = -(4)² + 5 (4) + 1 = -16+21 = 5 units

Part C

Now, we need to determine the value for g for which height would be maximum.

Looking at the expression that determines height, -g² + 5g + 1, we see that the coefficient of g² is negative. Hence the equation would represent a downward facing parabola, which means that the function H(g) will have a maxima point.

To find out the maxima point, differentiate H(g) with respect to g, and equate the resulting expression to zero.

\frac{d(H(g)}{dg} = -2g + 5 = 0

⇒ 2g = 5

⇒ g = 2.5

So at g = 2.5, the height of the water in the pool is maximum. [Note: nearest tenth means rounding till the first decimal point, hence the answer is g=2.5]

nalin [4]3 years ago
7 0

Answer:

(a)H(g)=-\frac{g^3}{3}+ \frac{5g^2}{2}+g\\(b)H(1)=3.17\\H(2)=9.33\\H(3)=16.5\\H(4)=22.67\\(c)g=5.19 gallons

Step-by-step explanation:

(A)

Rate at which pool is filled = 8g\² + 3g - 4

Rate at which water leaves the pool = 9g\² - 2g - 5

The rate at which the height of the pool is changing =Rate In-Rate Out

\alpha = 8g\² + 3g - 4 -( 9g\² - 2g - 5)\\=8g^2+3g-4-9g^2+2g+5\\\frac{dH(g)}{dg} =-g^2+5g+1\\H(g)=\int(-g^2+5g+1)dg\\H(g)=-\frac{g^3}{3}+ \frac{5g^2}{2}+g

(B)

Let water height be H

H(g)=-\frac{g^3}{3}+ \frac{5g^2}{2}+g\\H(1)=-\frac{1^3}{3}+ \frac{5^2}{2}+1=3.17\\H(2)=-\frac{2^3}{3}+ \frac{5(2)^2}{2}+2=9.33\\H(3)=-\frac{3^3}{3}+ \frac{5(3)^2}{2}+3=16.5\\H(4)=-\frac{4^3}{3}+ \frac{5(4)^2}{2}+4=22.67

(C)The water will reach its greatest height when the derivative of the Height Function is zero.

\frac{dH(g)}{dg} =-g^2+5g+1=0\\-g^2+5g+1=0\\g=-0.19,5.19\\

At g=5.19 gallons the height of the water will reach its greatest height.

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1- The total value of the Lucas coins dumped out of his piggy bank was $ 5.

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1- Given that when Lucas dumped the coins out of his piggy bank, he noticed that there were only nickels and dimes, and the number of nickels was twice the number of dimes, to determine, if there were 50 nickels, what was the total value of the Lucas coins dumped out of his piggy bank, the following calculation must be performed:

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Therefore, the total value of the Lucas coins dumped out of his piggy bank was $ 5.

2- Since when Franco dumped the coins out of his piggy bank, he noticed that there were only nickels and quarters, and the number of quarters was six more than half the number of nickels, to determine, if the total value of the coins Franco and Lucas dumped out of each piggy bank was the same, how many coins did Franco dump out of his piggy bank, the following calculation must be performed:

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  • 8 x 0.25 + 6 x 0.25 = 2 + 1.5 = 3.5
  • 16 x 0.05 = 0.8
  • 3.5 + 0.8 = 4.3
  • 10 x 0.25 + 6 x 0.25 = 2.5 + 1.5 = 4
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  • 10 + 6 + 20 = 36

Therefore, Franco dumped out 36 coins from his piggy bank (16 quarters and 20 nickels).

3- Since when Callie dumped the coins out of her piggy bank, she noticed that there were only nickels, dimes and quarters, and the number of dimes was one more than twice the number of quarters, and there were half as many quarters as nickels, y the coins dumped out of Callie's piggy bank had a total value equal to that of the coins dumped out of Franco's and Lucas' piggy banks combined, to determine what was the total value of the nickels and dimes dumped out of Callie's piggy bank, the following calculation should be performed:

  • Nickel = 0.05
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Therefore, there is no possible solution, as neither combination gives a total of $ 10, which is the combined total of Lucas and Franco's coins.

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