Can anyone help me with this plz?

Weston completed a hypothesis test and found that he could not reject the null hypothesis. Which of the following is a valid rea

yKpoI14uk [10]

The answer to the statistical question presented above would be letter B. The z-statistic lies in the critical region. If Weston completed a hypothesis test and found that he could not reject the null hypothesis, then it is valid to say that the z-statistic lies in the critical region.

5 0

4 years ago

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Suppose that news spreads through a city of fixed size of 700000 people at a time rate proportional to the number of people who

Gnoma [55]

Answer:

y'(t) = k(700,000-y(t)) k>0 is the constant of proportionality

y(0) =0

Step-by-step explanation:

(a.) Formulate a differential equation and initial condition for y(t) = the number of people who have heard the news t days after it has happened.

If we suppose that news spreads through a city of fixed size of 700,000 people at a time rate proportional to the number of people who have not heard the news that means

<em>dy/dt = k(700,000-y(t)) </em>where k is some constant of proportionality.

Since no one has heard the news at first, we have

<em>y(0) = 0 (initial condition) </em>

We can then state the initial value problem as

y'(t) = k(700,000-y(t))

y(0) =0

8 0

3 years ago

The approximate distance of the moon from Earth is 4 x 105 km and the average approximate distance from the Earth to Venus is 4

Otrada [13]

Wouldn’t it be 8 km farther bc earth to Venus is 420 km and earth to moon is 428 km. 428-420= 8

7 0

4 years ago

A random sample of 180 microbiology students were asked how many science classes he or she was enrolled in August 1990. The resu

frutty [35]

Answer:

$z=\frac{1.83-1.94}{\sqrt{\frac{1.48^2}{180}+\frac{1.62^2}{180}}}}=-0.673$

$p_v =2*P(z$

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we FAIL to reject the null hypothesis, and a would NOT be a significant difference in the two means

Step-by-step explanation:

Data given and notation

$\bar X_{1}=1.83$ represent the mean in 1990

$\bar X_{2}=1.94$ represent the mean for 2005

$s_{1}=1.48$ represent the sample deviation for 1990

$s_{2}=1.62$ represent the sample standard deviation for 2005

$n_{1}=180$ sample size for 1990

$n_{2}=180$ sample size for 2005

t would represent the statistic (variable of interest)

$\alpha=0.05$ significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the means for the two groups are different, the system of hypothesis would be:

Null hypothesis: $\mu_{1}=\mu_{2}$

Alternative hypothesis: $\mu_{1} \neq \mu_{2}$

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

$z=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

$z=\frac{1.83-1.94}{\sqrt{\frac{1.48^2}{180}+\frac{1.62^2}{180}}}}=-0.673$

What is the p-value for this hypothesis test?

Since is a bilateral test the p value would be:

$p_v =2*P(z$

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we FAIL to reject the null hypothesis, and a would NOT be a significant difference in the two means

8 0

4 years ago

HELLLLLPPPPPP

aleksley [76]

(3p, x+4) Is what I'm gonna go for.

8 0

4 years ago