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pashok25 [27]
3 years ago
9

Complete the recursive formula of the arithmetic sequence -17, -8, 1, 10,... a(1)= a(n)=a(n-1)+

Mathematics
1 answer:
hichkok12 [17]3 years ago
8 0

To find a(1), simply look at the first term, which is -17. This gives a starting point for the recursive formula.

Then, we want to write the recursive formula as a(n) = a(n - 1) + c, where c is the number you add to a term to get the next term. You can see from the values given that you are adding 9 to each term to get the next one, so the recursive formula would be a(n) = a(n - 1) + 9.

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8 0
3 years ago
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5 0
3 years ago
Caren held 260 of the shares for herself and sold the rest in equal amounts to six investors. How many shares does each investor
notsponge [240]

Answer:

40 shares each and $3,000 each

Step-by-step explanation:

The computation is shown below:

For the number of shares

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= 40 shares

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As we can see that the value of the shares is less than the amount liable by each investor

So each investor is liable for $3,000

And, the liability of Caren is

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5 0
3 years ago
1. List the cubes of -2, -1, 0, 1, 2, 3, and 4.
Arlecino [84]
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5 0
4 years ago
What’s the answer help please I need to pass this class
almond37 [142]

c.\ f(x)=\dfrac{18}{x}-9\ \text{and}\ g(x)=\dfrac{18}{x+9}\\\\\text{in f(x), solve for x}\\\\\dfrac{18}{x}-9=y\ \ \ \ |+9\\\\\dfrac{18}{x}=y+9\\\\\dfrac{18}{x}=\dfrac{y+9}{1}\ \ \ \ |\text{cross multiply}\\\\x(y+9)=18\ \ \ \ |:(y+9)\\\\x=\dfrac{18}{y+9}\to f^{-1}(x)=\dfrac{18}{x+9}

5 0
3 years ago
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