All categories

3 years ago

What is 5/10 - 3/10 simplify your answer

Mathematics

2 answers:

Ulleksa [173]3 years ago

7 0

The denominators of the fractions are the same, therefore you can just subtract the numerators and you're done.

$\frac{5}{10} -\frac{3}{10} =\frac{2}{10}=\frac{1}{5}$

If you had different denominators, you would have to multiply one or both of the equation by a common factor to get the denominators to be the same.

For example, if you have $\frac{4}{25} -\frac{1}{5}$ , you would multiply the second equation by a number that makes its denominator 25. 5 times 5 is 25, so:

$=\frac{4}{25} -(\frac{1}{5} *\frac{5}{5} )\\=\frac{4}{25} -\frac{5}{25} \\=-\frac{1}{25}$

<h3>Answer:</h3>

$\frac{1}{5}$

vodka [1.7K]3 years ago

6 0

Answer:

1/5

Step-by-step explanation:

5/10 -3/10 = 2/10, which simplifies to 1/5. Because they have common denominators, you just subtract the numerator and the denominator stays the same. 2/10, both the numerator and denominator are divisible by 2, so 2/2 is 1 and 10/2 is 5, giving you 1/5.

You might be interested in

Anna makes 120 dolls each month to sell. This month, she increases the number of dolls she makes by 30%. How many dolls does Ann

Tresset [83]

30% = .3

120 x .3 = 40

120 + 40 = 160

Anna makes 160 dolls

5 0

3 years ago

Solve 41-9+(8×2.3)-15+(2.1×4)

dsp73

(8x2.3)= (18.4)
(2.1x4)= (8.4)
Now you should have:
41-9+18.4-15+8.4
9+18= 27
15+8.4= 23.4
Should have:
41-27-23.4= -9.4

6 0

3 years ago

Given that Cosecant (t) = negative StartFraction 13 Over 5 EndFraction for Pi less-than t less-than StartFraction 3 pi Over 2 En

Sergio [31]

Answer:

$\bold{cot(t) =\dfrac{12}{5}}$

Step-by-step explanation:

Given that:

$Cosec (t) = -\frac{13}5$

for $\pi < t < \frac{3 \pi}2$

That means, angle $t$ is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.

In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

$cosec^2\theta -cot^2\theta =1$

here, $\theta =t$

So, $cosec^2t-cot^2t=1$

$\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}$