End behavior: f. As x -> 2, f(x) -> ∞; As x -> ∞, f(x) -> -∞
x-intercept: a. (3, 0)
Range: p. (-∞, ∞)
The range is the set of all possible y-values
Asymptote: x = 2
Transformation: l. right 2
with respect to the next parent function:

Domain: g. x > 2
The domain is the set of all possible x-values
Answer: y= 3 times 2 to the power x. Second answer
Step-by-step explanation:
if you plug in 0 for x, y= 3x 1= 3
if you plug in 1 for x y= 3 x 2 = 6
Look at the x values and y values
(0,3) and (1, 6) on the graph. It matches answer number 2. Remember, 2 raised to the power 0 = 1 and 3 times 1 = 3. And 2 raised to the power 1 =2 and 3 times 2 = 6.
Answer:
Step-by-step explanation:e equation has a leading coefficient of 1 or if the equation is a difference of squares. The zero-factor property is then used to find solutions. ... Another method for solving quadratics is the square root property. The variable is squared.
Answer:
4th answer aka the last one
Step-by-step explanation: