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Gekata [30.6K]
3 years ago
10

P(A) = 0.50 P(B)= 0.80 P(A and B) = 0.20 . what is P(B\A)?

Mathematics
2 answers:
yawa3891 [41]3 years ago
6 0

Answer:

0.4

Step-by-step explanation:

Use the formula for conditional probability.

P(B|A) = P(A&B)/P(A) = 0.20/0.50 = 0.4

storchak [24]3 years ago
3 0

Answer:  P(B/A) = 0.40.

Step-by-step explanation:  For any two events A and B, given that

P(A)=0.50,~~P(B)=0.80,~~P(A\cap B)=0.20.

We are to find the conditional probability of happening of event B given event A has already happened.

That is,

P(B/A)=?

From the formula for conditional probability, we have

P(B/A)=\dfrac{P(B\cap A)}{P(A)}\\\\\\\Rightarrow P(B/A)=\dfrac{P(A\cap B)}{P(A)}\\\\\\\Rightarrow P(B/A)=\dfrac{0.20}{0.50}\\\\\\\Rightarrow P(B/A)=0.40.

Thus, P(B/A) = 0.40.

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Marysya12 [62]

Answer:

97.10% probability that five or more of the original 2000 components fail during the useful life of the product.

Step-by-step explanation:

For each component, there are only two possible outcomes. Either it works correctly, or it does not. The probability of a component falling is independent from other components. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 2000, p = 1-0.995 = 0.005

Approximate the probability that five or more of the original 2000 components fail during the useful life of the product.

We know that either less than five compoenents fail, or at least five do. The sum of the probabilities of these events is decimal 1. So

P(X < 5) + P(X \geq 5) = 1

We want P(X \geq 5)

So

P(X \geq 5) = 1 - P(X < 5)

In which

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2000,0}.(0.005)^{0}.(0.995)^{2000} = 0.000044

P(X = 1) = C_{2000,1}.(0.005)^{1}.(0.995)^{1999} = 0.000445

P(X = 2) = C_{2000,2}.(0.005)^{2}.(0.995)^{1998} = 0.002235

P(X = 3) = C_{2000,3}.(0.005)^{3}.(0.995)^{1997} = 0.007480

P(X = 4) = C_{2000,4}.(0.005)^{4}.(0.995)^{1996} = 0.018765

P(X < 5) = P(X = 0) + `P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.000044 + 0.000445 + 0.002235 + 0.007480 + 0.018765 = 0.0290

P(X \geq 5) = 1 - P(X < 5) = 1 - 0.0290 = 0.9710

97.10% probability that five or more of the original 2000 components fail during the useful life of the product.

4 0
3 years ago
Each cylinder is 12 cm high with a diameter of 8 cm.
ludmilkaskok [199]

Answer:

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Step-by-step explanation:

h = 12 cm\\d = 8cm\\r =d/2 = 8/2 =4\\V = ?\\V =\pi r^2h\\\\V= 3 \times 4^2\times12\\V = 576 cm^3

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0.35 as a fraction is 35 over 100. An equivalent to this is 7 over 20
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Answer:

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Answer:

A. log9 3=x

Step-by-step explanation:

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