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2 years ago

Decrease 18•4 in the ratio 3:8

Mathematics

1 answer:

andrezito [222]2 years ago

8 0

Answer:

6.9

Step-by-step explanation:

Since you are supposed to decrease the number in the ratio 3:8 or 3/8 you take the small number that is 3 to be the numerator and 8 to be the denominator then multiply it by 18.4.

That is 18.4×3:8= 184/10×3/8=6.9

So to decrease a number you multiply it with the smallest number as the numerator and the big number as the denominator

To increase a number you multiply it with the big number as the numerator and the small number to be the denominator

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What is the equation of the line that passes through the point (-3, 0) and has a slope of -1/3?

ANTONII [103]

Answer:

Y=-1/3x-1

Step-by-step explanation:

Y-0=-1/3(x+3)

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2 years ago

A person owns two shops. this year the telephone bill for the first job was $640 less than four times a telephone bill for the s

KIM [24]

Answer: F=bill for first shop=4S-$630; S=bill for second shop

F+S=$3265 Substitute for F

4S-$630+S=$3265

5S=$3895

S=$779 ANSWER 1: The bill for the second shop was $779

F=4S-$630

F=4($779)-$630

F=$3116-$630=$2486 ANSWER 2: The bill for the first shop was $2486.

CHECK:

F+S=$3265

$2486+$779=$3265

$3265=$3265

explanation:

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3 years ago

Renna pushes the elevator button, but the elevator does not move. The mass limit for the elevator is 450 kilograms (kg), but Ren

liraira [26]

The picture below has both of the answers to your problem.

7 0

3 years ago

Read 2 more answers

Find the surface area of the cylinder formed by the net. Use 3.14 for π.

sineoko [7]

Answer:

138.16 square feet

Step-by-step explanation:

The surface area of the cylinder consists of one rectangle and two circles.

1. The radius of the circle is 4 ft, then the area of the circle is

$A_{circle}=\pi r^2 =\pi \cdot 4^2 =16\pi \ ft^2$

2. The width of the rectangle is 1.5 ft, the length of the rectangle is the circumference of the circle.

Find the circumference:

$C=2\pi r=2\pi \cdot 4=8\pi \ ft$

Hence,

$A_{rectangle}=1.5\cdot 8\pi =12\pi \ ft^2$

3. The surface area of the cylinder is

$SA=2A_{circle}+A_{rectangle}=\\ \\=2\cdot 16\pi +12\pi =32\pi +12\pi =44\pi \approx \\ \\\approx 44\cdot 3.14=138.16\ ft^2$

8 0

2 years ago

Answer the question in the picture

nekit [7.7K]

Recall the angle sum identities:

$\sin(x+y)=\sin x\cos y+\cos x\sin y$

$\cos(x+y)=\cos x\cos y-\sin x\sin y$

Now,

$\tan(x+y)=\dfrac{\sin(x+y)}{\cos(x+y)}=\dfrac{\sin x\cos y+\cos x\sin y}{\cos x\cos y-\sin x\sin y}$

Divide through numerator and denominator by $\cos x\cos y$ to get

$\tan(x+y)=\dfrac{\tan x+\tan y}{1-\tan x\tan y}$

Next, we use the fact that $x,y$ lie in the first quadrant to determine that

$\sin x=\dfrac12\implies\cos x=\sqrt{1-\sin^2x}=\dfrac{\sqrt3}2$

$\cos y=\dfrac{\sqrt2}2\implies\sin x=\sqrt{1-\cos^2x}=\dfrac1{\sqrt2}$

So we then have

$\tan x=\dfrac{\sin x}{\cos x}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}$

$\tan y=\dfrac{\sin y}{\cos y}=\dfrac{\frac1{\sqrt2}}{\frac{\sqrt2}2}=1$

Finally,

$\tan(x+y)=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3\approx3.73$

4 0

2 years ago