8) x - 5y = -15 x - 2y = -12
2 answers:
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To find out the largest number of snack bags that Rashad could make, we need to find the GCF of 24 and 56
Because,
GCF of 24 and 56 is the largest possible number that divides 24 and 56 exactly without any remainder. The factors of 24 and 56 are 1, 2, 3, 4, 6, 8, 12, 24 and 1, 2, 4, 7, 8, 14, 28, 56 respectively.
There are 3 commonly used methods to find the GCF of 24 and 56 - long division, Euclidean algorithm, and prime factorization.
By Prime factorisation :
Prime factorization of 24 and 56 is (2 × 2 × 2 × 3) and (2 × 2 × 2 × 7) respectively.
As visible, 24 and 56 have common prime factors. Hence, the GCF of 24 and 56 is 2 × 2 × 2 = 8.
By Euclidean algorithm :
As per the Euclidean Algorithm, GCF(X, Y) = GCF(Y, X mod Y) where X > Y and mod is the modulo operator.
Here X = 56 and Y = 24
- GCF(56, 24) = GCF(24, 56 mod 24) = GCF(24, 8)
- GCF(24, 8) = GCF(8, 24 mod 8) = GCF(8, 0)
- GCF(8, 0) = 8 (∵ GCF(X, 0) = |X|, where X ≠ 0)
Therefore, the value of GCF of 24 and 56 is 8.
By Long division :
GCF of 24 and 56 is the divisor that we get when the remainder becomes 0 after doing long division repeatedly.
- Step 1: Divide 56 (larger number) by 24 (smaller number).
- Step 2: Since the remainder ≠ 0, we will divide the divisor of step 1 (24) by the remainder (8).
- Step 3: Repeat this process until the remainder = 0.
The corresponding divisor (8) is the GCF of 24 and 56.
Hence,
Hence,Rashad can make 8 snack bags
Learn more about GCF at : brainly.com/question/11444998
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Answer:
0.01863, yes preference
Step-by-step explanation:
given that a class consists of 12 boys and 12 girls. The teacher picks five students to present their work to the rest of the class and says that the five students are being selected at random
Here selecting any 5 students from the group of total 24 students is combination because order does not matter.
Total no of ways of selecting any 5 from total 24 =
No of ways of selecting only 5 girls = No of ways of selecting random 5 girls from total 12 girls
=
a) the probability be that all five students
selected are girls=
b) Since the probability for selecting all girls is very small and near to 0, it is unusual to select all girls if done at random. Hence the teacher had a preference for girls.