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Blizzard [7]
3 years ago
8

I need help I need to find x​

Mathematics
1 answer:
dolphi86 [110]3 years ago
4 0
Cross multiply
5*27=135
3*x=3x

set equal to one another
3x=135

solve for x
135/3=x
45=x

x=45 minutes
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6x+2y=<br> 6x+2y=<br> \,\,16<br> 16<br> 2x-2y=<br> 2x−2y=<br> \,\,32<br> 32
Ivanshal [37]

Answer:

x = 6, y = -8

Step-by-step explanation:

First we take the equations side by side and put them like this:

 6x + 2y = 16

+ 2x - 2y = 32

8x = 48

Then solve for x.

x = 6

Then insert x back into either equation

2(5) - 2y = 32

10 - 2y = 32

solve for y,

y = -10

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3 years ago
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8 0
3 years ago
What is b1 and r of geometrical sequence if b3 −b1 = 16 and b5 −b3 = 144.
Naily [24]

Answer:

b1 = 2 ; r = 3

Step-by-step explanation:

Given that :

if b3 −b1 = 16 and b5 −b3 = 144.

For a geometric series :

Ist term = a

Second term = ar

3rd term = ar^2

4th term = ar^3

5th term = ar^4 ;...

If b3 - b1 = 16;

ar^2 - a = 16

a(r^2 - 1) = 16 - - - (1)

b5 - b3 = 144

ar^4 - ar^2 = 144

ar^2(r^2 - 1) = 144 - - - - (2)

Divide (1) by (2)

a(r^2 - 1) / ar^2(r^2 - 1) = 16 /144

a / ar^2 = 1 / 9

ar^2 = 9a

Substitute for a in ar^2 - a = 16

9a - a = 16

8a = 16

a = 2

From ar^2 - a = 16

2r^2 - 2 = 16

2r^2 = 16 + 2

2r^2 = 18

r^2 = 18 / 2

r^2 = 9

r = √9

r = 3

Hence ;

a = b1 = 2 ; r = 3

7 0
3 years ago
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